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kobusy [5.1K]
3 years ago
12

Find the Area and Perimeter!

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

Area of a triangle is 1/2 x base x height.

base = 12

Height = x+6

Area = 1/2 * 12 * x+6

Area = 1/2 * 12x * 72

Area = 6x + 36



Perimeter is the sum of the 3 sides:

x-7 + 12 + 2x+5

3x -2 + 12

3x+10


The last choice is the correct answer.



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y<6

Step-by-step explanation:

You will solve it like a one-step equation but just leave the less then symbol. so anything less then 6 is your answer

3 0
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If 18 is added to a certain number and the sum is divided by 6, the result is 1 more than 14 of the original number. Find the or
Katyanochek1 [597]
The original number is 72 


(18+x)/6 = 1+14 
1/6x + 3 = 1 + 14 (Distribute)
1/6x + 3 = (1+14) (Combine Like Terms)
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5 0
3 years ago
Express 3360 as a product of prime factors<br> PLS HELP ME !!!!!!!!
anyanavicka [17]

Answer:

7*5*3*2^5

Step-by-step explanation:

3360/2

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7 0
3 years ago
Which expression is equivalent to sqrt2/^3sqrt2
zimovet [89]

The given expression is \frac{\sqrt{2}}{\sqrt[3]{2}}

This can be simplified using the radical properties as below

\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\   \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\

Now using exponent properties we can write

\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\

7 0
3 years ago
Read 2 more answers
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