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oksian1 [2.3K]
3 years ago
9

4x + 2(x + 8) = -19+ x

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0

4x + 2(x + 8) = -19 + x

4x + 2x + 16 = -19 + x

6x + 16 = -19 + x

6x + 35 = x

-5x = 35

x = -7

Vlada [557]3 years ago
5 0

Answer: x= -7

Step-by-step explanation:

4x + 2(x+8)= -19+x

4x+2x+16= -19+x

6x+16= -19+x

6x-x+16= -19

6x-x= -19-16

5x= -35

x= -7

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Answer:

15 miles/hour = 0.25 miles/minute

The cyclist would have traveled 5 miles in 20 minutes.

Step-by-step explanation:

15 miles per hour is written as

15 miles/hour

To convert 15 miles/hour to miles/minute

From 1 hour = 60 minutes

∴ 15 miles/hour = 15 miles/ 60 minutes

= (15/60) miles/minute

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To calculate how many miles the cyclist will travel in 20 minutes

That is, Time, t = 20 minutes

Velocity, v = 15 miles/hour = 0.25 miles/minute

Distance, s = ??

From,

Velocity = \frac{Distance}{Time}\\

∴Distance = Velocity × Time

Distance = 0.25 miles/minute × 20 minutes

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Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
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Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

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