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gizmo_the_mogwai [7]

3 years ago

15

Steve's nut world increases the weight of its big almond bag by 3 ounces seven big almond bags now weigh a total of 126 ounces .

How many ounces did the old big almond bag weigh

1 answer:

Yuliya22 [10]3 years ago

3 0

126/7=18 (so that's 18 ounces per bag)
now subtract the 3 ounces that were added to each bag:
18-3=15
so the old almond bag weighed 15 ounces

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use the pythagorean theorem to find the missing side length. 2 write sin, cosine, tangent of each angel.

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1) $x=5\sqrt{3}$

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$cos(a)=11/14$

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$tan(a)=5\sqrt{3}/11$

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Step-by-step explanation:

The Pythagorean Theorem is:

$a^{2}=b^{2}+c^{2}$

Where a is the hypotenuse and b and c are the legs.

The missing side lenght is one of the legs, then you must solve for one of them. Therefore, this is:

$x=\sqrt{(14yd)^{2}-(11yd)^{2}}=5\sqrt{3}yd$

MEASURE OF ANGLE:

Keep the identities on mind:

$sin\alpha=opposite/hypotenuse$

$cos\alpha=adjacent/hypotenuse$

$tan\alpha=opposite/adjacent$

Susbstitute values, then:

$sin(a)=5\sqrt{3}/14$

$sin(b)=11/14$

$cos(a)=11/14$

$cos(b)=5\sqrt{3}/14$

$tan(a)=5\sqrt{3}/11$

$tan(b)=11/5\sqrt{3}$

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