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Mazyrski [523]
4 years ago
9

TIMMMMMEDDDDD Analyze the diagram below and complete the instructions that follow.

Mathematics
2 answers:
Murljashka [212]4 years ago
8 0

Answer:

The correct answer is,

B) OSQ= PSR and OSP=QSR

I just finished the test and it was correct

lukranit [14]4 years ago
6 0
Angle OSP and angle QSR are congruent because angles that are complementary to the same angle are congruent.

Angle OSQ and angle PSR are congruent because they are both right angles, meaning they both are 90 degrees.

Final Answer: angle OSQ and PSR are congruent; angle OSP and QSR are congruent
You might be interested in
Use (a) the midpoint rule and (b) simpson's rule to approximate the below integral. ∫ x^2sin(x) dx with n = 8.
MaRussiya [10]

Answer:

midpoint rule =  5.93295663

simpson's rule = 5.869246855

Step-by-step explanation:

a) midpoint rule

\int\limits^b_a {(x)} \, dx≈ Δ x (f(x₀+x₁)/2 + f(x₁+x₂)/2 + f(x₂+x₃)/2 +...+ f(x_{n}_₂+x_{n}_₁)/2 +f(x_{n}_₁+x_{n})/2)

Δx = (b − a) / n

We have that a = 0, b = π, n = 8

Therefore

Δx = (π − 0) / 8 = π/8

Divide the interval [0,π] into n=8 sub-intervals of length Δx = π/8 with the following endpoints:

a=0, π/8, π/4, 3π/8, π/2, 5π/8, 3π/4, 7π/8, π = b

Now, we just evaluate the function at these endpoints:

f(\frac{x_{0}+x_{1}  }{2} ) = f(\frac{0+\frac{\pi}{8}   }{2} ) = f(\frac{\pi }{16})=\frac{\pi^{2}sin(\frac{\pi }{16})  }{256} = 0.00752134

f(\frac{x_{1}+x_{2}  }{2} ) = f(\frac{\frac{\pi }{8} +\frac{\pi}{4}   }{2} ) = f(\frac{3\pi }{16})=\frac{9\pi ^{2} sin(\frac{3\pi }{16}) }{256} = 0.19277080

f(\frac{x_{2}+x_{3}  }{2} ) = f(\frac{\frac{\pi }{4} +\frac{3\pi}{8}   }{2} ) = f(\frac{5\pi }{16})=\frac{25\pi ^{2} sin(\frac{5\pi }{16}) }{256} = 0.80139415

f(\frac{x_{3}+x_{4}  }{2} ) = f(\frac{\frac{3\pi }{8} +\frac{\pi}{2}   }{2} ) = f(\frac{7\pi }{16})=\frac{49\pi ^{2} sin(\frac{7\pi }{16}) }{256} = 1.85280536

f(\frac{x_{4}+x_{5}  }{2} ) = f(\frac{\frac{\pi }{2} +\frac{5\pi}{8}   }{2} ) = f(\frac{9\pi }{16})=\frac{81\pi ^{2} sin(\frac{7\pi }{16}) }{256} = 3.062800704

f(\frac{x_{5}+x_{6}  }{2} ) = f(\frac{\frac{5\pi }{8} +\frac{3\pi}{4}   }{2} ) = f(\frac{11\pi }{16})=\frac{121\pi ^{2} sin(\frac{5\pi }{16}) }{256} = 3.878747709

f(\frac{x_{6}+x_{7}  }{2} ) = f(\frac{\frac{3\pi }{4} +\frac{7\pi}{8}   }{2} ) = f(\frac{13\pi }{16})=\frac{169\pi ^{2} sin(\frac{3\pi }{16}) }{256} = 3.61980731

f(\frac{x_{7}+x_{8}  }{2} ) = f(\frac{\frac{7\pi }{8} +\pi    }{2} ) = f(\frac{15\pi }{16})=\frac{225\pi ^{2} sin(\frac{\pi }{16}) }{256} = 1.69230261

Finally, just sum up the above values and multiply by Δx = π/8:

π/8 (0.00752134 +0.19277080+ 0.80139415 + 1.85280536 + 3.062800704 + 3.878747709 + 3.61980731 + 1.69230261) = 5.93295663

b) simpson's rule

\int\limits^b_a {(x)} \, dx  ≈ (Δx)/3 (f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃) + 2f(x₄) + ... + 2f(x_{n-2}) + 4f(x_{n-1}) + f(x_{n}))

where Δx = (b−a) / n

We have that a = 0, b = π, n = 8

Therefore

Δx = (π−0) / 8 = π/8

Divide the interval [0,π] into n = 8 sub-intervals of length Δx = π/8, with the following endpoints:

a = 0, π/8, π/4, 3π/8, π/2, 5π/8, 3π/4, 7π/8 ,π = b

Now, we just evaluate the function at these endpoints:  

f(x₀) = f(a) = f(0) = 0 = 0

4f(x_{1} ) = 4f(\frac{\pi }{8} )=\frac{\pi^{2}\sqrt{\frac{1}{2}-\frac{\sqrt{2} }{4}   }  }{16} = 0.23605838

2f(x_{2} ) = 2f(\frac{\pi }{4} )=\frac{\sqrt{2\pi^{2}  } }{16} = 0.87235802

4f(x_{3} ) = 4f(\frac{3\pi }{8} )=\frac{9\pi^{2}\sqrt{\frac{\sqrt{2} }{4}-\frac{{1} }{2}   }  }{16} = 5.12905809

2f(x_{4} ) = 2f(\frac{\pi }{2} )=\frac{\pi ^{2} }{2} = 4.93480220

4f(x_{5} ) = 4f(\frac{5\pi }{8} )=\frac{25\pi^{2}\sqrt{\frac{\sqrt{2} }{4}-\frac{{1} }{2}   }  }{16} = 14.24738359

2f(x_{6} ) = 2f(\frac{3\pi }{4} )=\frac{9\sqrt{2\pi^{2}  } }{16} = 7.85122222

4f(x_{7} ) = 4f(\frac{7\pi }{8} )=\frac{49\pi^{2}\sqrt{\frac{1}{2}-\frac{\sqrt{2} }{4}   }  }{16} = 11.56686065

f(x₈) = f(b) = f(π) = 0 = 0

Finally, just sum up the above values and multiply by Δx/3 = π/24:

π/24 (0 + 0.23605838 + 0.87235802 + 5.12905809 + 4.93480220 + 14.24738359 + 7.85122222 + 11.56686065 = 5.869246855

7 0
3 years ago
Dennis has 30 plums and 42 apricots. he wants to put the fruit in bag so that each bag has the same number of like fruit. how ma
kondaur [170]

Solve.

<span>Mr. Madison picked 80 pieces of fruit on Thursday.</span>Add.

<span>042412+ 40<span>80
</span></span>
5 0
3 years ago
What do the following two equations represent? <br> y = 6x -2 <br> 2x – 12y = 24
maxonik [38]

Answer: Intersecting, but not perpendicular lines

Step-by-step explanation:

3 0
3 years ago
Diana has been saving nickels and dimes. She opened up her piggy bank and determined that it contained 48 coins worth $4.50. Det
tino4ka555 [31]

Answer:

6 Nickels

42 Dimes

Step-by-step explanation:

There are 48 coins in total (nickels and dimes). Let the number of nickels be "n" and the number of dimes be "d". So we can write:

n + d = 48

or

n = 48 - d

In dollars, we know nickels are worth 0.05 and dimes are worth 0.10. In total there is $4.50, so we can write:

0.05n + 0.10d = 4.50

Now replacing first equation [n = 48 - d] into 2nd, we get and equation in "d" and solve for d first:

0.05n + 0.10d = 4.50\\0.05(48-d) + 0.10d = 4.50\\2.4-0.05d+0.10d=4.50\\0.05d=4.50-2.4\\0.05d=2.1\\d=\frac{2.1}{0.05}=42

So, there are 42 dimes.

We know from before, n = 48 - d, so

n = 48 - 42 = 6

There are 6 nickels

3 0
3 years ago
Use the Distributive Property to simplify -4(-a + 2)
marysya [2.9K]

Answer:

4a-8

Step-by-step explanation:

(-4×a)+(-4×2)

Distributive property

4 0
3 years ago
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