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3 years ago

What is the area of in square centimeters, of the trapezoid 8.6, 6.4, 12.9

Mathematics

1 answer:

zloy xaker [14]3 years ago

4 0

You have to let us see a picture but you take length x width and divide by 2 to get your answer

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Identify the initial amount a and the growth factor b in the exponential function

Olenka [21]

F(t)=1.4^t
a)a=1, b=0.4 
b)a=1.4, b=0<<<< 
c)a=1.4, b=t 
d)a=1, b=1.4
Hope this helped!!

7 0

3 years ago

14 - 2 ( 1+2) answer

riadik2000 [5.3K]

That would be 8. first parenthesis, then multiply, then subtract.

4 0

3 years ago

Read 2 more answers

A coin is tossed 5 times. Find the probability that all are heads. Find the probability that at most 2 are heads.

fenix001 [56]

Answer:

1/32

15/32

Step-by-step explanation:

For a fair sided coin,

Probability of heads, P(H) = 1/2

Probability of tails P(T) = 1/2

For a coin tossed 5 times,

P( All heads)

= P(HHHHH),

= P (H) x P(H) x P(H) x P(H) x P(H)

= (1/2) x (1/2) x (1/2) x (1/2) x (1/2)

= 1/32 (Ans)

For part B, it is easier to just list the possible outcomes for

"at most 2 heads" aka "could be 1 head" or "could be 2 heads"

"One Head" Outcomes:

P(HTTTT), P(THTTT) P(TTHTT), P(TTTHT), P(TTTTH)

"2 Heads" Outcomes:

P(HHTTT), P(HTHTT), P(HTTHT), P(HTTTH), P(THHTT), P(THTHT), P(THTTH), P(TTHHT), P(TTHTH), P(TTTHH)

If we count all the possible outcomes, we get 15 possible outcomes representing "at most 2 heads)

we know that each outcome has a probability of 1/32

hence 15 outcomes for "at most 2 heads" have a probability of

(1/32) x 15 = 15/32

8 0

3 years ago

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Which of the following measures is equivalent to 3,300 grams?

max2010maxim [7]

Answer:

C. 3.3 kg.

Step-by-step explanation:

There are 1000 grams in a kilogram.

So 3,000 g = 3300/1000

= 3.3 kg.

8 0

2 years ago

What two numbers multiply to 10 and add to -29 ?

Degger [83]

Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

so
x^2+29x+10=0
a=1
b=29
c=10
x= $\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}$
x= $\frac{-29+/- \sqrt{841-40} }{2}$
x= $\frac{-29+/- \sqrt{801} }{2}$
x= $\frac{-29+/- 3\sqrt{89} }{2}$

x= $\frac{-29- 3\sqrt{89} }{2}$ or $\frac{-29+ 3\sqrt{89} }{2}$
those are the 2 numbers
aprox=-28.65 and -0.349

5 0

2 years ago

Read 2 more answers