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Margaret [11]
3 years ago
14

Two stores sell the same refrigerator for the same original price. Store A advertises that the refrigerator is on sale for 15% o

ff the original price. Store B advertises that it is reducing the refrigerator’s price by $150. When Stephanie compares the sale prices of the refrigerator in both stores, she concludes that the sale prices are equal. Which equation models this situation?
Let p represent the refrigerator’s original price.

A. 0.85p = p – 150
B. 0.85(p – 150) = p
C. 0.15p = p – 150
D. 0.15p = p + 180
Mathematics
2 answers:
NISA [10]3 years ago
6 0
<span>The correct answer is option A. Since store A is giving a discount of 15% on the original price i.e.$ p. Then, the price after discount will be equal to $ 0.85p . And, the second store B offers $150 less than the original price p i.e the price after reduction is $p-$150. Since both the proces after reduction are equal. Thus, $ 0.85p = $p-$150</span>
makvit [3.9K]3 years ago
4 0

Answer:

A. 0.85p = p – 150

Step-by-step explanation:

I took the test and got it right

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Answer:

Yes

Step-by-step explanation:

4'9" is 57 inches. Jannet is taller than that, so should go without a booster seat.

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<em>Feet to Inches</em>

1 foot is 12 inches, so 4 feet is 4×12 = 48 inches. Adding 9 inches to that gives ...

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3 years ago
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I need help on 8 9 and 10
Lerok [7]

9. x + (y - 3 - 4x + 2( 3x - (-y - 1) + 2y) - 3x)

= x + (y - 3 - 4x + 2 (3x + y - 1) +  2y - 3x)
= x + (y - 3 - 4x + 6x + 2y - 2 + 2y - 3x)
= (x - 4x + 6x - 3x) + (y + 2y + 2y) - (3+2)
= 0 + 5y - 5
= 5y - 5 (or simplified as 5(y-1)

10. 6 + (-a -3(b + 6(a - b)+4a) - 2b)
= 6 + (-a - 3(b + 6a - 6b + 4a) -2b)
= 6 + (-a - 3b + 18a - 18b + 12a - 2b)
= 6 + (-a + 18a + 12a) + (-3b - 18b - 2b)
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2 years ago
A running club has 90 members.
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Step-by-step explanation:

5 0
3 years ago
A parking meter contains nickels and quarters worth $7.70. There are 54 coins in all. Find how many of each there are.
OleMash [197]

Let's assume there is n number of nickels coin and q number of quaters coin.

Given that there are 54 coins in total. So, sum of n and q must be equal to 54.

So, n + q =54.

Hence, q = 54 - n ...(1)

Now 1 nickel is worth of $0.01 nickel. So, n nickel will woth of 0.01n.

Similarly q quarters will worth of 0.25q.

Given that a parking meter contains nickels and quarters worth $7.70. So, sum of 0.01n and 0.25q will be equal to 7.70. Therefore,

0.01n + 0.25q = 7.70

From equation (1) we can plug in q=54-n in the above equation. So,

0.01n + 0.25 (54-n) = 7.70

0.01n + 13.5 -0.25n = 7.70

-0.24n + 13.5 = 7.70

-0.24n = 7.70 - 13.5

-0.24n = -5.8

\frac{-0.24n}{-0.24} =\frac{-5.8}{-0.24}

So, n= 24.167

Hence, n= 24 ( rounded to nearest integer).

Next step is to plug in n=24 in equation (1). So,

q = 54 - 24 = 30.

Hence, there will be 24 nickel and 30 quarter.

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