Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Half the distance of AC (6)
Answer:
The cosine function that is represented in the graph is:
Option B. f(x)=cos (x-pi/4)-1
Step-by-step explanation:
The parent function is cos x.
cos x at x=0 has the maximum value 1.
The graph is shifted to the right (x-pi/4) with a maximum value 0 at x=pi/4, then the graph is shifted downward 1 unit.
Then f(x)=cos (x-pi/4)-1
Please, see the attached graph:
The blue line is the parent function y=cos x
The red line is the graph given
Answer:
112
4 to the second power is 16, multiply by 7 get 112
Step-by-step explanation:
Answer:
#1. 5x - 24
#2. 10x - 1
#3. 10x -14
#4. 6x - 12
#5. 3x63 + 5x^2 - 3
#6. 12a + 43
#7. -7x + 5y + 28
#8. 3x + 3(not sure about the last exponent because It was really blury to see :/
Step-by-step explanation:
Sorry I cant do the last because I have to now :) I will try to answer it next time if It isn't already answered :)
