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marta [7]
3 years ago
15

What is the average speed of a car that travels 80 km in 1.5 hours

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

53 1/3 km/h

Step-by-step explanation:

The car is going at 80km in 1.5 hours, so if you divide that value you get 26 2/3 km for every half hour, now you would want to multiply this times 2 to find the value for every hour, so then this would give you the answer 53 and 1/3 kilometers per hour.

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AB has endpoints at (-4,5) and (4,-3) using the midpoint formula what is the midpoint segment
Mamont248 [21]

Answer:

(0,1)

Step-by-step explanation:

5 0
2 years ago
After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the particular type of soil ide
dimaraw [331]

Answer:

The revised probabilities are;

The probability of finding soil with oil  = 0.8  

The probability of finding soil with good oil = 0.16

The probability of finding medium quality oil =  0.64

Step-by-step explanation:

The given probability of finding soil with high quality oil, P(QO) = 0.20

The probability of finding soil with medium-quality oil, P(OM) = 0.80

The probability of finding soil with no oil, P(ON) = 0.2

Therefore, given that the probability of finding soil with no oil = 0.2, we have;

The probability of finding soil with oil, P(OP) = 1 - the probability of finding soil with no oil

P(OP) = 1 - 0.2 = 0.8

Which gives;

The probability, P(FG) of finding soil with oil and that the oil is good is given as follows;

P(FG) = P(QO) × P(OP) = 0.2 × 0.8 = 0.16

The probability of finding good oil = 0.16

Similarly;

The probability of finding medium quality oil P(FM) =  P(OM) × P(OP) = 0.8 × 0.8 = 0.64

Which gives the revised probability as follows;

The probability of finding soil with oil, P(OP) = 0.8  

The probability of finding soil with good oil, P(FG) = 0.16

The probability of finding medium quality oil, P(FM) =  0.64.                

3 0
2 years ago
I'm having trouble with algebraic fractions . 3/2n-8/3=-29/12
nadezda [96]

what we can do is hmmmm get the LCD of all fractions, and multiply both sides by that LCD, let's see, we have denominators of 2, 3 and 12, so we can use the LCD of 12, and multiply both sides by 12 to do away with the denominators.

\bf \cfrac{3}{2}n-\cfrac{8}{3}=-\cfrac{29}{12}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{3}{2}n-\cfrac{8}{3} \right)=12\left( -\cfrac{29}{12} \right)}\implies (6)3n-(4)8=(1)-29 \\\\\\ 18n-32=-29\implies 18n=3\implies n=\cfrac{3}{18}\implies n=\cfrac{1}{6}

5 0
3 years ago
Explain why you cannot factor the trinomial x(to the power of 2)−12x+6
Vladimir [108]

Answer:

See below

Step-by-step explanation:

You cannot find two whole number integers that give a sum of -12 and a product of 6.

-1 + -11 = -12, but (-1)(-11) = 11, which isn't 6

-2 + -10 = -12, but (-2)(-10) = 20, which isn't 6

...and so on...

4 0
1 year ago
Read 2 more answers
HELP! ! easy work for a lot points! please help me!
kiruha [24]

Answer:

Provide a question pls :)

Step-by-step explanation:

Pls mark brainliest lol

6 0
3 years ago
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