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emmasim [6.3K]
2 years ago
8

Michael has $1,059.35 in his checking account. He is going to spend $466.43 on a new television, and he will spend the rest on s

peakers that cost $43.00 each. Which of the following inequalities would determine the maximum number of speakers, x, Michael can buy without spending more money than he has in his account?
A.
$466.43 < $43.00x + $1,059.35
B.
$1,059.35 < $43.00x + $1,059.35
C.
$466.43 + $43.00 + x < $1,059.35
D.
$43.00x + $466.43 < $1,059.35
Mathematics
2 answers:
andrey2020 [161]2 years ago
7 0

Answer:

D

Step-by-step explanation:

its $43 each and he wants to buy more than one so that means thats x

that marks out C

so 43.00x +466.43 is less than 1,059.35

I really feel like one of them should have less than/greater than or equal to sign but without I think its D

sesenic [268]2 years ago
3 0

Answer:

D. $43.00x + $466.43 < $1,059.35

Step-by-step explanation:

He has $1,059.35.

The amount of speakers he buys is x.

Each speaker is $43.00, and he is buying one television, which is $466.43.

All of the speakers he buys and(+) the television must be less than $1,059.35 because that's all he has. It cannot be more, which is why the equation is $43.00x + $466.43 < $1,059.35.

Hope this helps!

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A data set lists weights​ (lb) of plastic discarded by households. The highest weight is 5.31 ​lb, the mean of all of the weight
a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 ​lb, and the standard deviation of the weights is s=1.968 lb.

This means that \mu = 2.088, \sigma = 1.968

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This is X - \mu = 5.31 - 2.088 = 3.222

The difference is of 3.222 lbs.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

This is the z-score. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.31 - 2.088}{1.968}

Z = 1.64

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly​ high, is the weight of 5.31 lb​ significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

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