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topjm [15]
3 years ago
12

What is -7/10,-1/10,-2/5,-3/10,-1/2 in decimal form and from least to greatest

Mathematics
1 answer:
Tresset [83]3 years ago
6 0

Answer

Decimal forms:

-0.7

-0.1

-0.4

-0.3

-0.5

Least to greatest

Since the sign is negative, the least no. Become greater and vice versa

Hence the order is

-0.7<-0.5<-0.4<-0.3<-0.1

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Find the value of x + y for x = 75.9 and y = 2.65.
Schach [20]
The answer is 78.55
all you need to do is add 75.9+2.65
8 0
3 years ago
Read 2 more answers
Sofia tem 52 triângulos retângulos isósceles iguais. Ela quer fazer quadrados usando alguns desses triângulos. Ela pode fazer qu
oee [108]

Answer:

Portanto, o Sofia pode fazer 6 tamanhos diferentes

Step-by-step explanation:

A fim de sermos capazes de determinar efetivamente quantos quadrados de diferentes tamanhos podem ser formados a partir do triângulo isósceles 52, resolvemos isso usando a fórmula

2 (n + 1) Onde n = 0 e todos os inteiros positivos

em outro para obter um tamanho diferente para os quadrados, temos que adicionar mais triângulos para aumentar o tamanho

a) quando n = 0

2 (0 + 1) = 2 × 1 = 2 triângulos isósceles iguais

A união de 2 triângulos isósceles forma um quadrado. Este é o primeiro quadrado

= 1 quadrado

b) quando n = 1

2 (1 + 1) = 2 × 2 = 4 triângulos isósceles iguais = 1 quadrado

c) quando n = 2

2 (2 + 1) = 2 × 3 = 6 triângulos isósceles iguais = 1 quadrado

d) quando n = 3

2 (3 + 1) = 2 × 4 = 8 triângulos isósceles iguais = 1 quadrado

e) quando n = 4

2 (4 + 1) = 2 × 5 = 10 triângulos isósceles iguais = 1 quadrado

f) quando n = 5

2 (5 + 1) = 2 × 6 = 12 triângulos isósceles iguais = 1 quadrado

Adicionamos o número total de triângulos usados

2 + 4 + 6 + 8 + 10 + 12 = 42 triângulos

42 triângulos de 52 triângulos formariam 6 quadrados com tamanhos diferentes

Vamos fazer mais um, onde n = 6

g) quando n = 6

2 (6 + 1) = 2 × 7 = 14 triângulos isósceles iguais = 1 quadrado

2 + 4 + 6 + 8 + 10 + 12 + 14 = 56 triângulos

Isso já excedeu o número dado de triângulos em questão.

Portanto, o Sofia pode fazer 6 tamanhos diferentes de quadrados usando 42 triângulos isósceles iguais

8 0
3 years ago
A piece of wire 10 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
Luda [366]

The maximum and the minimum total area inclosed are 6.25m² and 2.72m²

What is an area?

⇒ The area is the region bounded by the shape of an object.

Calculation:

Let x is the length of the piece of wire for the equilateral triangle, whose side will then be (x/3) m long.

⇒  (10 - x) = length of the remaining piece for the square, whose side will then be (10 - x)/4 m long.

h = height of the equilateral triangle = h = a×√3/2 = (x/3)×(√3/2)

(Where a is the side of the triangle)

A(x) = Total area of the square formed + Total area of the triangle formed

Then    A(x) = [(10 - x)/4]²+ (1/2)(x/3)(x/6)√3

                   = [(100 - 20x + x²)/16] +  (√3/36)x² .

           

The maximum total area enclosed :

⇒ The entire 10m length should be allocated to the square because a square produces more area per unit of its perimeter than does a triangle.

Thus if all square, then x=0 and A(0)  = [2.5]² = 6.25 m² = Maximumarea

If all triangle, then x = 10  and  A(10) = (1.732/36)(100) = 4.811 m² .

So, the maximum area occurs when it's all used to make a square of side 2.5 m.

The minimum total area enclosed is :

⇒ We want a relatively small square and a small triangle.

 We are going to Find x by setting the derivative of A(x) to zero.

d[ A(x)]/dx  =   [(-20 + 2x)/16] + (2√3/36)x = 0

                  =  -5/4  + (1/8)x  +  (√3/18)x  = 0

                 x =  5/[4 (1/8 + √3/18)]  = 5/[ 4(0.125 + 0.09622)] = 5/(0.88489)  ⇒5.65 m perimeter of the triangle                  

             

and (10 - x) = 4.35 = perimeter of square

And  

A(5.65) = [4.35/4]² +  (√3/36)(5.65)²

             = 1.1827 from the square+1.5358 from the triangle

             =  2.719m² total area = Minimum area

⇒ On rounding off it will be 2.72m²

Hence the maximum and the minimum areas are 6.25m² and 2.72m²

Learn more about the area here:

brainly.com/question/25292087

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Questions:  A piece of wire 10m long is cut into two pieces. one piece is bent into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a. a maximum? b. minimum?

8 0
1 year ago
The best player on a basketball team makes 75​% of all free throws. The​ second-best player makes 65​% of all free throws. The​
Sliva [168]

Answer:

Dude I get ur struggle

Step-by-step explanation:

Alright I wont give the exact answers but here is what you do. You multiply the number of attemps by the percentage and you get the number of freethorws they would make.

5 0
3 years ago
A rhombus has coordinates A(-6, 3), B(-4, 4), C(-2, 3), and D(-4, 2). What are the coordinates of rhombus A′B′C′D′ after a 90° c
Liula [17]

We are given that the coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)

To solve this problem, we must plot this on a graphing paper or graphing calculator to clearly see the movement of the graph. If we transform this by doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)

 

And the final transformation is translation by 3 units left and 2 units down. This can still be clearly solved by actually graphing the plot. The result of this transformation would be:

<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>

7 0
3 years ago
Read 2 more answers
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