Which two values of x are roots of the polynomial below x^2-11x+17
1 answer:
<u>Answer</u>
9.14 and 1.86
<u>Explanation</u>
x²-11x+17
The first thing is to equate it to zero.
x²-11x+17 = 0
x²-11x = -17
x² - 11x + (11/2)² = -17 + (11/2)²
(x² - 11/2)² = -17 + 121/4
(x - 11/2)² = 13.25
x -11/2 = √13.25 or x - 11/2 = -√13.25
x = √13.25 + 11/2 x = -√13.25 + 11/2
= 3.64 + 5.5 = -3.64 + 5.5
= 9.14 = 1.86
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