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3 years ago

Which two values of x are roots of the polynomial below x^2-11x+17

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Answer

9.14 and 1.86

Explanation

x²-11x+17

The first thing is to equate it to zero.

x²-11x+17 = 0

x²-11x = -17

x² - 11x + (11/2)² = -17 + (11/2)²

(x² - 11/2)² = -17 + 121/4

(x - 11/2)² = 13.25

x -11/2 = √13.25 or x - 11/2 = -√13.25

x = √13.25 + 11/2 x = -√13.25 + 11/2

= 3.64 + 5.5 = -3.64 + 5.5

= 9.14 = 1.86

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In the given question, we are given that the quadrilateral MNOP is a parallelogram.

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