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Alenkinab [10]
2 years ago
10

In the arithmetic sequence {-9, -4, 1, 6, 11,…} what is the common difference? Enter your answer as a number

Mathematics
1 answer:
Levart [38]2 years ago
4 0

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\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

What is the common difference in the sequence -9, -4, 1, 6, 11,...?

\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

The common difference is a number you add or subtract in order to get to the next term; in this case, we add.

The common difference of this arithmetic sequence is 5.

So in order to get to the next term, we add 5.

-9+5=-4

-4+5=1

1+5=6

6+5=11, etc.,

<h3>Henceforth the common difference of this sequence is 5.</h3>

<h3>Good luck.</h3>

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3n^2=6-17n I need Vertex form please.
nasty-shy [4]

Answer:

3( n + \frac{17}{6} )² - \frac{361}{12} = 0

Step-by-step explanation:

3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0

3( n² + 2 × \frac{17}{6} n + ( \frac{17}{6} )² - ( \frac{17}{6} )² - 2 ) = 0

3( n + \frac{17}{6} )² - 3 × \frac{289}{36} - 6 = 0

3( n + \frac{17}{6} )² - \frac{361}{12} = 0

8 0
3 years ago
Population A and Population B both have a mean height of 70.0 inches with an SD of 6.0. A random sample of 50 people is picked f
Alex

Answer:

Sample mean from population A has probably more accurate estimate of its population mean than the sample mean from population B.

Step-by-step explanation:

To yield a more accurate estimate of the population mean, margin of error should be minimized.

margin of error (ME) of the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in the given confidence level(z-score or t-score)
  • s is the standard deviation of the sample (or of the population if it is known)
  • N is the sample size

for a given confidence level, and the same standard deviation, as the sample size increases, margin of error decreases.

Thus, random sample of 50 people from population A, has smaller margin of error than the sample of 20 people from population B.

Therefore, sample mean from population A has probably more accurate estimate of its population mean than the sample mean from population B.

7 0
4 years ago
PLEASE HELPP MEEEEE
pav-90 [236]
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.

Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11

Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
6 0
3 years ago
HELP ASAP PLEASE!!
Mama L [17]

Answer:

Step-by-step explanation:

According to the table, function g(x) reaches the max height of 33, approx.

The equation of motion is f(x) = -16x^2 + 42x + 12.  We need to determine the maximum of this function.  To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.

Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.

So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6

6 0
3 years ago
Help if u know it please!!!
Ulleksa [173]
Mean: add all the numbers, then dived the sum by hwo many numbers there are.
72.3 + 74.5 + 81.1 + 72.3 + 75.6 + 79 = 754.8
754.8 ÷ 6 = 75.8
Mean = 75.8°

Median: Put all the number in order from lowest to highest. The middle number is the median. If there are two numbers in the middle, add them then divide the sum by 2.
72.3, 72.3, 74.5, 75.6, 79, 81.1
74.5 + 75.6 = 150.1
150.1 ÷ 2 = 75.05 ~ 75
Median = 75°
5 0
3 years ago
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