2Na + Cl₂ → 2NaCl
Explanation:
The reaction of sodium metal with chlorine gas to produce sodium chloride is a typical example of synthesis reaction.
Combination or synthesis involves the formation of a single product from two or more reactants.
A + B ⇒ C
In this kind of chemical reaction, a single product is formed or some compounds by the union of elements is notable.
The driving force for this category of chemical reaction is the large and negative heat of formation of the product.
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"Confounding variable" is the choice among the following choices given in the question that best describes two <span>or more explanatory variables that are not separated. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has come to your help.</span>
Answer:
As the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Explanation:
As the object is moving towards the lens then in that case first the image will form between the focus and double the distance of focus.
So here the image is diminished
now when the object is at large distance from from lens then its image will form at focus and it is of very small size
Now as the object comes closer to the lens till the object distance is 2F the image size will increase but smaller then object size
Now when object is between F and 2F then the image size will be more than object size and it will increase to infinite magnification
So overall we can say that as the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Answer:
Explanation:
mass attached m = .14 kg
force constant k = 5N / m
displacement
= amplitude of oscillation
A = .03 m
A ) period of motion =
= 2 x 3.14
T = 1.05 s
B ) maximum speed of block = angular velocity x amplitude
= (2π /T) x A
= (2 x 3.14 x .03) / 1.05
= .1794 m / s
17.94 cm /s
C )
maximum acceleration = angular velocity² x amplitude
= (2π /T)² x A
= (2π /1.05)² x .03
= 1.073 m / s²
D )
position
S = A cos ωt , ω is angular velocity
S = .03 cos(2πt /T)
= .03 cos 5.98 t
v =ω A sin(2πt /T)
= 5.98 x .03 sin5.98t
= .1794 sin5.98t
acceleration = ω²A sin5.98t
= 1.073 sin5.98t