All categories

3 years ago

A drop in pitch as a vehicle passes is known as the effect

Physics

2 answers:

malfutka [58]3 years ago

5 0

This is known as the Doppler effect.

Georgia [21]3 years ago

4 0

The Doppler Effect...

<span>It describes an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move toward (or away from) each other.</span>

You might be interested in

Which of the following scientists taught physics in the United States?

Sergio039 [100]

<span>Subrahmanyan Chandrasekhar

</span>

6 0

3 years ago

Read 2 more answers

I need help with this problem.

tamaranim1 [39]

Answer:

Explanation:

Line CD

7 0

3 years ago

A sand mover at a quarry lifts 2,000 kg of sand per minute a vertical distance of 12 m. The sand is initially at rest and is dis

Marianna [84]

Answer:

Explanation:

Power is defined as the rate of workdone.

Power = Workdone/time taken

Given Workdone = Force * distance

Power = Force * distance/time taken

Power = mgd/t (F = mg)

m = mass of the sand in kg

g = acceleration due to gravity in m/s²

d = vertical distance covered in metres

t = time taken in seconds

Given m = 2000kg, d = 12m, t = 1min = 60secs, g = 9.8m/s²

Power = 2000*9.8*12/60

Power = 3920Watts

Minimum rate of power that must be supplied to this machine is 3920Watts or 3.92kW

5 0

3 years ago

Enter your answer in the provided box. The mathematical equation for studying the photoelectric effect is hν = W + 1 2 meu2 wher

siniylev [52]

Answer:

$v = 4.44 \times 10^5 m/s$

Explanation:

By Einstein's Equation of photoelectric effect we know that

$h\nu = W + \frac{1}{2}mv^2$

here we know that

$h\nu$ = energy of the photons incident on the metal

$W$ = minimum energy required to remove photons from metal

$\frac{1}{2}mv^2$ = kinetic energy of the electrons ejected out of the plate

now we know that it requires 351 nm wavelength of photons to just eject out the electrons

so we can say

$W = \frac{hc}{351 nm}$

here we know that

$hc = 1242 eV-nm$

now we have

$W = \frac{1242}{351} = 3.54 eV$

now by energy equation above when photon of 303 nm incident on the surface

$\frac{1242 eV-nm}{303 nm} = 3.54 eV + \frac{1}{2}(9.1 \times 10^{-31})v^2$

$4.1 eV = 3.54 eV + (4.55 \times 10^{-31}) v^2$

$(4.1 - 3.54)\times 1.6 \times 10^{-19}) = (4.55 \times 10^{-31}) v^2$

$8.96 \times 10^{-20} = (4.55 \times 10^{-31}) v^2$

$v = 4.44 \times 10^5 m/s$

6 0

3 years ago

A car accidently rolls off acliff. As it leaves the cliff it has a horizontal of 13m/s, it hits they ground 60m from the shoreli

zimovet [89]

Answer:

jsudyve elected

Explanation:

hsydvr r r

8 0

3 years ago