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Alenkasestr [34]
2 years ago
8

Plz help me I’m a desperate little boy

Physics
1 answer:
Neporo4naja [7]2 years ago
5 0

It is the first one. But if you have this question you are not a little boy

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Steve and Carl are driving from Scranton to Bridgeport, a distance of 180 miles. If their speed averages 60 miles an hour, how l
Vikki [24]

Time = (distance) / (speed)

Time = (180 miles) / (60 mi/hr)

Time = (180/60) (mi-hr/mi)

<em>Time = 3 hours</em>

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3 years ago
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What is the mani difference between kentic energy and potential energy
AlekseyPX
Kinetic energy is stored energy that is released, for example, a fast-moving roller coaster down a slope. Potential energy is energy that has stored energy, for example, a stretched rubber band.
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3 years ago
Gyroscopic wander can be divided in to two categories, one is DRIFT, what is the other?
Tju [1.3M]

Gyroscopic wander can be divided into two categories and these are:

  1. Drift
  2. Topple

<h3>What is gyroscopic wander?</h3>

Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.

Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:

  • Drift
  • Topple

Read more on gyroscopic wander here: brainly.com/question/12168194

#SPJ12

4 0
1 year ago
What type of transfer of solar energy helps to contribute to the "greenhouse effect"
Paul [167]
The greenhouse effect<span> occurs when Earth's atmosphere traps </span>solar<span>radiation ... infrared (IR) and other </span>types<span> of radiation that are invisible to the human eye. UV radiation has a shorter wavelength and a higher </span>energy<span> level </span>
8 0
2 years ago
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An electron travels 0.01 m across an electric potential difference of 6 x 10^6 V. What is the force exerted on the electron? Typ
JulijaS [17]

Answer:

9.6\cdot 10^{-11}N

Explanation:

The force experienced by a charged particle immersed in an electric field is

F=qE

where

q is the charge of the particle

E is the strength of the electric field

For a uniform field, we can write

E=\frac{\Delta V}{d}

where

\Delta V is the potential difference

d is the distance travelled

So we can rewrite the force as

F=\frac{q\Delta V}{d}

In this problem:

q=1.6\cdot 10^{-19}C is the charge of the electron

\Delta V=6\cdot 10^6 V is the potential difference

d = 0.01 m is the distance covered

Substituting, we find the force:

F=\frac{(1.6\cdot 10^{-19})(6\cdot 10^6)}{0.01}=9.6\cdot 10^{-11}N

3 0
2 years ago
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