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Alenkasestr [34]

2 years ago

8

Plz help me I’m a desperate little boy

1 answer:

Neporo4naja [7]2 years ago

5 0

It is the first one. But if you have this question you are not a little boy

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Which contributes most to our average dose of background radiation?

Anuta_ua [19.1K]

C) Natural and Artificial sources

6 0

3 years ago

Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply

umka21 [38]

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

The three particles involved in this problem are:

Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is $m_p = 1.67 \cdot 10^{-27} kg$
Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton: $m_e = 9.11 \cdot 10^{-31} kg$

We can now analyze each of the given statement:

__Protons and neutrons have similar mass. --> TRUE

__Protons and electrons have similar mass. --> FALSE, the electron is much lighter

__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier

__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons

__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons

__Electrons are smaller than a proton or a neutron. --> TRUE

Learn more about atoms:

brainly.com/question/2757829

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac

Anarel [89]

Answer:

$R = 24.3 m$

Explanation:

As we know that the orbital speed is given as

$v = \sqrt{\frac{GM}{R + h}}$

here we know that

v = 5500 m/s

$R = 4.48 \times 10^6 m$

$h = 630 km$

now we have

$5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}$

$M = 2.34 \times 10^24 kg$

now acceleration due to gravity of planet is given as

$a = \frac{GM}{R^2}$

$a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}$

$a = 7.7 m/s^2$

now range of the projectile on the surface of planet is given as

$R = \frac{v^2 sin2\theta}{g}$

$R = \frac{14.6^2 sin(2\times 30.8)}{7.7}$

$R = 24.3 m$

3 0

3 years ago

Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 65.3 ◦ . The velo

yanalaym [24]

Answer:

Plane will 741.6959 m apart after 1.7 hour

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is = $102^{\circ}-65.3^{\circ}=36.7^{\circ}$

Speed of first plane = 730 m/h

So distance traveled by first plane = 730×1.7 = 1241 m

Speed of second plane = 590 m/hr

So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, $r^2$ representing the distance between the planes, we see that:

$r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295$

r = 741.6959 m

3 0

3 years ago

Citrus2011 [14]

Answer:

net force is positive downward..B

6 0

3 years ago