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Cerrena [4.2K]
3 years ago
6

At a concert 2/5 of the people were men, there were 3 times as many women as children. If there were 45 more men than children,

how many people were there at the concert.
Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

This involves creating some equations.

First, these are what the letters I used stand for:

c = children

w = women

m = men

x = total population

Then, we must make an equation for each statement.

2/5x = m (2/5 of the people are men)

3c = w (there are 3 times as many women than children)

45+c = m (there are 45 more men than children)

Now, let's start plugging in our numbers:

x = all the men, women, and children

2/5(m+w+c) = m

2/5 (45+c +3c + c) = m     [Now simplify]

2/5 (45 + 5x) = m       [Now Distribute]

2/5(45) + (2/5)(5x) = m

2c + 18 = m    [Above we stated that there were the same amount as men as c +45]

2c + 18 = 45 +c     [Now set equal to c]

2c (-c) +18 = 45 +c (-c)

c+18 (-18) = 45 (-18)

c = 27

Now that we know that there was 27 children, we can plug 27 in for c in the other equations.

MEN = 27 + 45

WOMEN = 3(27)

CHILDREN = 27

Now add those three answers to find your total!

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The sum of two numbers is 95. If the larger is increased by twice the smaller, the result is 120. Find the numbers.
adelina 88 [10]
Hello!

You can make two expressions based on what you know

let x equal the larger number
let y equal the smaller number

x + y = 95
x + 2y = 120

We can use elimination to get rid of x

You can subtract the two equation to get rid of x

-y = -25

Since y is negative we can multiply both sides by -1 to make y positive

y = 25

Now we can put this into one of the other equations to find x

x + 25 = 95

subtract 95 from both sides

x = 70

The answers are 70 and 25

Hope this helps!
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