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Gemiola [76]
3 years ago
9

Will give brainliest. These are composite figures, find the area of the figure and round your answer to one decimal place, if ne

cessary.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer: Answer: 1333.25Step-by-step explanation: The area of the rectangle is 23x23 = 529. Area of the square is 804.25. So add them toget her and you get your answer.

Step-by-step explanation: (Same person that answered your other question I have two accounts)

You might be interested in
22.a) A fruit vendor bought 1948 oranges on a Thursday and sold 750 of them on the same day.
iVinArrow [24]

Answer: Ksh 6144

Step-by-step explanation:

On Thursday, a fruit vendor bought 1948 oranges on a Thursday and sold 750. The number of oranges left will be: = 1948 - 750 = 1198

On n Friday, he sold 240 more oranges than on Thursday. This means the number of oranges sold is: = 240 + 750 = 990.

The number for f oranges left will then be: = 1198 - 990 = 208

On Saturday, he bought 560 more

oranges, the total oranges that the vendor has now will be:

= 208 + 560 = 768

Since sold all the oranges he had at a price of Ksh. 8 each, the amount if money made will be:

= Ksh 8 × 768

= Ksh 6144

The vendor made Ksh 6144

7 0
2 years ago
What dose 4i(-6+i) +
Yuliya22 [10]

Step-by-step explanation:

-4 - 24 i

3 0
3 years ago
Solve the inequality.
Dima020 [189]

Answer:

Step-by-step explanation:

x + 8 < - 28

x < - 28 - 8

x < - 36

Option A is the correct answer

3 0
2 years ago
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
Andrew is selling tickets for the school play, and charges t dollars for adult tickets and 2 dollars for child tickets. On Monda
Andru [333]

Answer:

T=4 plz make brainlest answer

Step-by-step explanation:

Monday overall cost 36+5t

Tuesday overall cost 20+9t

36+5t=20+9t

-20 -20

16+5t =9t

-5t -5t

16=4t

t=4

Check

36+5t=20+9t (t=4)

36+20=20+36

It works

3 0
3 years ago
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