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Gemiola [76]
3 years ago
9

Will give brainliest. These are composite figures, find the area of the figure and round your answer to one decimal place, if ne

cessary.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer: Answer: 1333.25Step-by-step explanation: The area of the rectangle is 23x23 = 529. Area of the square is 804.25. So add them toget her and you get your answer.

Step-by-step explanation: (Same person that answered your other question I have two accounts)

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Find the area of the blue sector(s). The diameter is 14.
pav-90 [236]

The area of the entire circle is pi*(7)^2, or 49pi.


Due to the 90 degree angle, the area of the larger blue sector is


90

------- * 49 pi = 49/4 units^2

360


The area of the smaller blue sector is


48

------- 49 pi = (2/15)(49 pi) = 98 pi/15 units^2

360


The total area of the blue sectors is the sum of 98 pi/15 and 49 pi/4 (units^2):


59 units^2

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%205%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%3D%207x%20%2B%203x%20%5C%5C%20find%20%5C%3A%20the%20%5C
lana [24]

Answer:

5 {x}^{2}  + 2x = 7x + 3x \\ 5 {x}^{2}  + 2x = 10x \\ 5 {x}^{2}  = 10x - 2x \\ 5 {x}^{2}  = 8x \\ 5x = 8 \\ x =  \frac{8}{5}  = 1.6 \\ thank \: you

4 0
2 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
!!!! could anyone help on these two problems? find the value of each trigonometric ratio
Setler [38]

Answers:

  • sin(C) = 24/25
  • cos(Z) = 5/13

=============================================

Explanation:

The formulas we use are

  • sin(angle) = opposite/hypotenuse
  • cos(angle) = adjacent/hypotenuse

The fraction 15/39 reduces to 5/13 after dividing both parts by the GCF 3.

3 0
3 years ago
What is the volume of the right triangular prism shown?
ollegr [7]

<u>Given</u>:

The sides of the base of the triangle are 8, 15 and 17.

The height of the prism is 15 units.

We need to determine the volume of the right triangular prism.

<u>Area of the base of the triangle:</u>

The area of the base of the triangle can be determined using the Heron's formula.

S=\frac{a+b+c}{2}

Substituting a = 8, b = 15 and c = 17. Thus, we have;

S=\frac{8+15+17}{2}

S=\frac{40}{2}=20

Using Heron's formula, we have;

Area = \sqrt{S(S-a)(S-b)(S-c)}

Area = \sqrt{20(20-8)(20-15)(20-17)}

Area = \sqrt{20(12)(5)(3)}

Area = \sqrt{3600}

Area = 36

Thus, the area of the base of the right triangular prism is 36 square units.

<u>Volume of the right triangular prism:</u>

The volume of the right triangular prism can be determined using the formula,

V=\frac{1}{2}A_b h

where A_b is the area of the base of the prism and h is the height of the prism.

Substituting the values, we have;

V=\frac{1}{2}(60\times 15)

V=450

Thus, the volume of the right triangular prism is 450 cubic units.

8 0
3 years ago
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