Answer:
The function to represent the area a of the section inside the border is ![A=12x-x^2](https://tex.z-dn.net/?f=A%3D12x-x%5E2)
Step-by-step explanation:
Given section inside the border is
inches and
inches.
We need to write the function to represent the area of the section inside the border.
We can see the length of border is
and width of the border is
.
So, the area of the rectangle will be ![length\times width](https://tex.z-dn.net/?f=length%5Ctimes%20width)
The area
will be
![A=x(12-x)\\\\A=12x-x^2](https://tex.z-dn.net/?f=A%3Dx%2812-x%29%5C%5C%5C%5CA%3D12x-x%5E2)
So, the function to represent the area a of the section inside the border is ![A=12x-x^2](https://tex.z-dn.net/?f=A%3D12x-x%5E2)
Answer:
40 cm squared
Step-by-step explanation:
Area = length * width
10*4cm = 40 cm squared
Answer:
Step-by-step explanation:
x=50 hope it hleps
∠A = 24°
∠B = 87°
∠A = 24°
Explanation:
The sum of angles in a triangle is 180 degrees
let measure of angle A = ∠A
∠B = 15 more than three times the measure of angle A
∠B = 15 + 3∠A
∠C = 45° more than the measure of angle A
∠C = 45° + ∠A
∠A + ∠B + ∠C = 180° (sum of angles in a triangle)
∠A + 15 + 3∠A + 45° + ∠A = 180
collect like terms:
∠A + 3∠A + ∠A + 15 + 45 = 180
5∠A + 60 = 180
5∠A = 180 -60
5∠A = 120
∠A = 120/5
∠A = 24°
∠B = 15 + 3∠A = 15 + 3(24)
∠B = 87°
∠C = 45° + ∠A = 45° + 24°
∠C = 69°
Answer: The height of the mountain is 1,331.4 meters (approximately)
Step-by-step explanation: From the information given, the students were standing at point b which is 800 meters from the base of the mountain and the angle of elevation from that point is 59°. Assuming that the ground is level, we can derive a right angled triangle from this set of details and hence we have triangle ABC, where angle β is the reference angle, (59 degrees), BC is the distance from the students to the base of the mountain (800 meters) and the line AC is the height of the mountain.
The line AC is the opposite, since angle B is the reference angle, therefore we shall use the trigonometric ratio as follows;
Tan β = opposite/adjacent
Tan 59 = AC/800
Tan 59 x 800 = AC
1.6643 x 800 = AC
1331.44 = AC
AC ≈ 1331.4
Therefore the height of the mountain is approximately 1,331.4 meters