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3 years ago

23.6-2*3^0 divided by 2

1 answer:

8 0

First do any exponents: 3 to the 0 power would equal 1. Then multiply and divide in order: 2x1=2, 2/2=1. Then subtract: 23.6-1=22.6 :)

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How many solution does each graph have

SVEN [57.7K]

Answer:

one solution 

no solution 

infinity solutions 

Step-by-step explanation:

A: If the graphs of the equations intersect, then there is one solution that is true for both equations.

B; If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

C; If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations

4 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

steposvetlana [31]

Answer:

Step-by-step explanation:

(29, 35) (43, 21)

(21 - 35)/(43 - 29) = -14/14 = -1

y - 35 = -(x - 29)

y - 35 = -x + 29

y = -x + 64

3 0

3 years ago

The graph shown is a translation of the graph of f(x)=x^2. Write the function in vertex form.

Gnesinka [82]

$\sf \longrightarrow \: f(x) = {x}^{2}$

Write the parent function in the standard form I.e.

$\boxed{ \tt \:y =a(x - h) \times 2 + k }$

Where,

a = 1
h = 0
k = 0

$\sf \longrightarrow \:y= 1(x - 0)^{2} \times 2 + 0$

$\sf \longrightarrow \: y = (x - 0) ^{2} \times 2 + 0$

$\sf \longrightarrow \: y = {x}^{2} \times 2$

$\sf \longrightarrow \: y = 2{x}^{2}$

4 0

2 years ago

6(3u+4) please help I am in a classwork

frozen [14]

Answer:

18u+24

Step-by-step explanation:hope this helps xxx

7 0

2 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago