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Sedaia [141]
3 years ago
13

Shirley cuts a 133 m long rope into several pieces of length 3 1/2 m each. How many equal pieces of the rope does she get

Mathematics
1 answer:
liraira [26]3 years ago
5 0


38

explanation:
133 divided by 3.5
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DAVID PLZ HELP LAST ONE
Leto [7]

Answer:

1.D

2.c

Step-by-step explanation:

f(m/4)=8(m²/16)-4(m/4)

=m²/2-m

f(-4)=-3(-4)²+5(-4)

=-3(16)-20

=-48-20

=-68

3 0
3 years ago
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some friends went to a local movie theater and bought four large buckets of popcorn and six boxes of candy.The total for the sna
WARRIOR [948]

The total of 2 buckets of popcorn and 3 boxes of candy would be $23.25

To answer this question you need to form a set of simultaneous equations and solve them. We can do this by saying that a bucket of popcorn = P, and a box of candy = C. Then we can say:

4P + 6C = 46.50

P + C = 9.75

There are then two possible ways to solve; you can either say that C = 9.75 - P using the second equation and then substitute it into the first, or you can multiply the second equation by either 4 or 6 to cancel out P or C.

I’m going to multiply the second equation by 4:

4P + 4C = 39

Now we can subtract this for, the first equation:

4P + 6C = 46.50

4P + 4C = 39

2C = 7.50

C = 3.75

Now we can substitute this value of C into one of the equations to find P:

P + C = 9.75

P + 3.75 = 9.75

P = 6

And now to answer the question, you just multiply P by 2 and C by 3 and add them together, which gives you $23.25

I hope this helps! Let me know if you have any questions :)

6 0
3 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

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3 years ago
What is the answer so I could get the question​
qaws [65]

Answer:My answer is Temp-pH I

I don't know if it is right or not

6 0
3 years ago
Which one of these lines is the equation
yaroslaw [1]

Answer:

Line B - red line

Step-by-step explanation:

7 0
3 years ago
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