the table below:
Grade In favor Opposed Undecided Total
Grade 9 6 4 8 18
Grade 10 10 11 9 30
Grade 11 12 15 11 38
Grade 12 15 6 14 35
If the principal randomly selects a student in grade 10 from this survey,
the probability that the student is opposed to extending the school day
P ( student in grade 10 is opposed)= Number of student in opposed(grade10) / total number of students in grade 10
Number of student opposed who is in grade10 = 11
total number of students in grade 10 = 30
P( student in grade 10 is opposed)= 
= 0.37
the probability that the student is opposed to extending the school day= 0.37
Answer:
A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more
Step-by-step explanation:
Option A Versus Option B
Option A Option B
Day Amount Deposited Day Amount Deposited
0 $40,000.00 0 $1.00
1 $40,250.00 1 $2.00
2 $40,500.00 2 $4.00
...
30 $47,500 16 $65,536.00
Answer:
A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more
Answer:
2x+8-2y
Step-by-step explanation:
4x-2x+5+3-2y
2x+8-2y
Answer:
D
Step-by-step explanation:
The basic equation to solve this would be D = RT, which is
D is Distance
R is Rate (speed)
T is time
To find total distance D, we can find individual distances for two legs of the whole.
First Leg:
R = 8
T = a
D = 8a
Second Leg:
R = 7.5
T = b
D = 7.5b
Total distance D is:
D = 8a + 7.5b
Moreover, we know student runs 45 minutes in total hence a + b = 45 or we can say a = 45 - b, so we can replace this in the equation found:
D = 8a + 7.5b
D = 8(45 - b) + 7.5b
Answer choice D is right.
I believe it would be 2 units to the right
and 4 units down
