Answer:
an = 67 -11(n -1)
Step-by-step explanation:
The terms of your arithmetic sequence have a common difference of -11. The first term is 67.
These values can be used in the generic formula for the n-th term:
an = a1 +d(n -1) . . . . . . first term a1, common difference d
an = 67 -11(n -1) . . . . . formula for the n-th term
Answer:
Hey there!
Rafiq's error was that the other number is also changing. He had 4 x 8 and if he had 8 x 8, that would be twice as much, but he used 8 x 12 instead, and 12 is not 8.
Let me know if this helps :)
Answer:
Manuel made his first mistake in step 2 leading to the continuous mistakes
Final answer=185
Step-by-step explanation:
Manuel made at least one error as she found the value of this expression. 2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50) Step 1: 2(-20) + 3(-25) + 5(20) + 4(50) Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50) Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405 Identify the step in which Chris made her first error. After identifying the step with the first error, write the corrected steps and find the final answer.
2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50)
Step 1: 2(-20) + 3(-25) + 5(20) + 4(50)
Step 2: -40 - 75 + 100 +
200
Step 3: -115 + 300
Step 4: 185
Manuel made his first error in step 2 by combining two different terms into one as he has done
(3 + 2)(-20 + -25) and also (5 + 4)(20 + 50)
Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50)
Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405
He should have evaluated the terms separately as I have done above, giving us 185 as the final answer in contrast to his 405 final answer.
Okay so we have to figure out what percentage passed first let’s add all the percentages
25%+15%= 40%
Now subtract that from 100%
100%-40%= 60%
So 60% of the class passed
Now let’s use x to represent the total number of people on the class
x•0.6= 24
Now solve for x
x= 40
There are 40 people in the class we figure this out my converting 60% to 0.6 and multiplying it by 40 and getting 24 which is correct
