1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
y=3/4x
Step-by-step explanation:
Option D: Two irrational solutions
Explanation:
The equation is 
Subtracting 6x from both sides, we have,
Solving the equation using quadratic formula,
Simplifying the expression, we get,
Taking out the common terms and simplifying, we have,
Dividing by 3, we get,
Hence, the equation has two irrational solutions.
Given inequality
=> −2(x+1)≥3x+8
=>
now multiply with - on both sides.
As we know now sign will change
=> 5x >_ -10
Now divide by 5 on both sides
=> x >_ -2
HOPE IT HELPED YOU.
Multiply the first bracket by -2
Multiply the second bracket by 2
x-3-12+4x= 4x-10
- negative number times + positive number= - negative number
- negative number times -negative number = + positive number
x+ 4x-3-12= 4x-10
5x-15= 4x-10
Move 4x to the other side
5x-4x-15= 4x-4x-10
x-15= -10
Move -15 to the other side
x-15+15= -10+15
x= 5
Answer : x= 5
