Because arcsin or sin-1 only gives outputs that are in the first and fourth quadrant.
5pi / 6 is in the second quadrant.
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
Answer:
C, 15
Step-by-step explanation:
i looked it up
Answer:
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Step-by-step explanation:
9514 1404 393
Answer:
- (x -3)^2 +(y -5)^2 = 9
- x^2 +y^2 -6x -10y +25 = 0
Step-by-step explanation:
The standard form equation for a circle of radius r and center (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
For radius 3 and center (3, 5), this is ...
(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation
Expanding this and subtracting the constant on the right gives ...
x^2 -6x +9 +y^2 -10y +25 -9 = 0
x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation
