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Eva8 [605]
3 years ago
7

What is one specific form of diffusion

Biology
1 answer:
Alchen [17]3 years ago
3 0
<span>
is it facilitated diffusion? </span>
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Which statement best describes the life cycle of plants such as ferns? Plants have a two-part life cycle, spending part of their
Gemiola [76]

The correct answer is that ferns have two part in their life cycle: Diploid phase and haploid phase

The life cycle of a fern has two parts: sporophyte stage and gametophyte stage. The gametophyte stage of ferns are haploid which releases gametes and the sporophyte stage are diploid that produces spores. This kind of life cycle is known as the "alternation of generation".




4 0
3 years ago
Read 2 more answers
Which of the following is the largest ocean ecosystem, known for colonies of small, marine animals?
Anna11 [10]
Coral reefs
hope it helps
8 0
2 years ago
During which phase of mitosis are the spindle fibres formed around the sister chromatids?
Evgesh-ka [11]

Answer:

Metaphase

Explanation:

In prophase, spindle fibers start emerging from the centrosomes. In metaphase, the spindle fibers attach to the sister chromatids.

3 0
2 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
Chromosomes that have the same gene at the same location​
Nesterboy [21]

Answer:

The two chromosomes in a homologous pair are very similar to one another and have the same size and shape. Most importantly, they carry the same type of genetic information: that is, they have the same genes in the same locations. However, they don't necessarily have the same versions of genes.

Explanation:

Hope this helped, can i get a brainlest please? :)

8 0
2 years ago
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