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Oksanka [162]
2 years ago
8

Bob and Dan earned a total of $72

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

If Dan earns $x then Bob earns $3x ( 3 times as much as Dan ), then

x + 3x = 72 , that is

4x = 72 ( divide both sides by 4 )

x = 18

Thus

Dan earns $18 and Bob earns 3 × $18 = $54

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Use the rule for y= -6x +8 to find the output if the input is x=20
lisov135 [29]

Answer:

The output of the function y = -6x + 8 when the input is x = 20 is -112.

Step-by-step explanation:

y = -6x + 8

Input the value x = 20.

y = -6(20) + 8

Multiply -6 and 20.

y = -120 + 8

Add -120 and 8.

y = -112.

8 0
3 years ago
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If 4x -8y + 9 = 0 and 3y + Mx + 1 0 are parallel find the value of m
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Step-by-step explanation:

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2 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
Jane and sali cycled along the same 63 km route.
Alina [70]

Answer:

<em>Sali's speed was 18.75 km/h.</em>

Step-by-step explanation:

Jane took 3.5 hours to cycle the 63 km.

As,  Speed= \frac{Distance}{Time} , so the speed of Jane will be:  \frac{63}{3.5} km/h = 18 km/h

Suppose, the speed of Sali is  x km/h

Sali caught up with Jane when they had both cycled 30 km.

So, <u>the time required for Jane to cycle 30 km</u> = \frac{30}{18}=\frac{5}{3} hours and <u>the time required for Sali to cycle 30 km</u>  =\frac{30}{x} hours

Given that, Sali started to cycle 4 minutes or (\frac{4}{60}) or (\frac{1}{15}) hours after Jane started to cycle. So, the equation will be.......

\frac{5}{3}-\frac{30}{x}= \frac{1}{15}\\ \\ \frac{30}{x}= \frac{5}{3}-\frac{1}{15}\\ \\ \frac{30}{x}= \frac{24}{15}\\ \\ 24x=450\\ \\ x= \frac{450}{24}= 18.75

Thus, the speed of Sali was 18.75 km/h.

8 0
2 years ago
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