f
'
(
x
)
=
1
(
x
+
1
)
2
Explanation:
differentiating from first principles
f
'
(
x
)
=
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
f
'
(
x
)
=
lim
h
→
0
x
+
h
x
+
h
+
1
−
x
x
+
1
h
the aim now is to eliminate h from the denominator
f
'
(
x
)
=
lim
h
=0
(
x
+
h
)
(
x
+
1
)−
x
(
x
+
h
+
1)
h
(
x
+
1
)
(
x
+
h
+
1
)
f
'
(
x
)
=
lim
h
→
0
x
2
+
h
x
+
x
+
h
−
x
2
−
h
x
−
x
h
(
x
+
1
)
(
x+h
+
1
)
f
'
(
x
)
=
lim
h
→
0
h
1
h
1
(
x
+
1
)
(
x
+
h
+1
)
f
'
(
x
)
=
1
(
x
+
1
)
2
Answer:
See below ~
Step-by-step explanation:
<u>(a)</u>
The point (8, 28) represents that in the time of 8 minutes, 28 cm of the horse trough has been filled.
- 8 <u>minutes</u> 28 <u>centimeters</u>
<u></u>
<u>(b)</u>
<u>Finding the unit rate</u>
- No. of centimeters / min.
- 28 cm / 8 min
- <u>3.5 cm/min</u>
-7a + 5a < -(7-a) -(2a +1) Turns to
-7a +5a < -7 +a -2a -1 Which turns to
-2a < -1a -8 Which turns to
-1a < -8 Which turns to
1a > 8
:)
Answer: P(t)=25000(1.12)^t
Step-by-step explanation:
