Do a proportion
60/100= x/54
Cross multiply and divide
54 x 60= 3,240
3,240 divided by 100 is 32.4
Now subtract
54- 32.4= 21.6
Answer is $21.6
Answer: x=15
Step-by-step explanation:
Since these are supplementary angles, we know that if we add them together we would get 180 deg. so....
(7x-10)+ (6x-5)=180
Kay so now we can combine like terms.
13x-15=180
Now we can add 15 to both sides.
13x=195
Finally Divide 13 on both sides.
X would then now equal 15.
Answer:
Step-by-step explanation:
sub in all your x values into the linear equation it gives you
once you have your table you should be able to figure out the rest if the questions !!
Answer:
a.![P(E_1/A)=0.0789](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D0.0789)
b.
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c.![P(E_3/A)=0.526](https://tex.z-dn.net/?f=P%28E_3%2FA%29%3D0.526)
Step-by-step explanation:
Let
are the events that denotes the good drive, medium drive and poor risk driver.
![P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20](https://tex.z-dn.net/?f=P%28E_1%29%3D0.30%2CP%28E_2%29%3D0.50%2CP%28E_3%29%3D0.20)
Let A be the event that denotes an accident.
![P(A/E_1)=0.01](https://tex.z-dn.net/?f=P%28A%2FE_1%29%3D0.01)
![P(A/E_2=0.03](https://tex.z-dn.net/?f=P%28A%2FE_2%3D0.03)
![P(A/E_3)=0.10](https://tex.z-dn.net/?f=P%28A%2FE_3%29%3D0.10)
The company sells Mr. Brophyan insurance policy and he has an accident.
a.We have to find the probability Mr.Brophy is a good driver
Bayes theorem,![P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}](https://tex.z-dn.net/?f=P%28E_i%2FA%29%3D%5Cfrac%7BP%28A%2FE_i%29%5Ccdot%20P%28E_1%29%7D%7B%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7DP%28A%2FE_i%29%5Ccdot%20P%28E_i%29%7D)
We have to find ![P(E_1/A)](https://tex.z-dn.net/?f=P%28E_1%2FA%29)
Using the Bayes theorem
![P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D%5Cfrac%7BP%28A%2FE_1%29%5Ccdot%20P%28E_1%29%7D%7BP%28E_1%29%5Ccdot%20P%28A%2FE_1%29%2BP%28E_2%29P%28A%2FE_2%29%2BP%28E_3%29P%28A%2FE_3%29%7D)
Substitute the values then we get
![P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D%5Cfrac%7B0.30%5Ctimes%200.01%7D%7B0.01%5Ctimes%200.30%2B0.50%5Ctimes%200.03%2B0.20%5Ctimes%200.10%7D)
![P(E_1/A)=0.0789](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D0.0789)
b.We have to find the probability Mr.Brophy is a medium driver
![P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395](https://tex.z-dn.net/?f=P%28E_2%2FA%29%3D%5Cfrac%7B0.03%5Ctimes%200.50%7D%7B0.038%7D%3D0.395)
c.We have to find the probability Mr.Brophy is a poor driver
![P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526](https://tex.z-dn.net/?f=P%28E_3%2FA%29%3D%5Cfrac%7B0.20%5Ctimes%200.10%7D%7B0.038%7D%3D0.526)
<u>Answer and Step-by-Step explaination:</u>
Area =Length time Width
Area= 21*21
Area=441