Forces 1 N, 2 N and 3 N act at a point in direction parallel to the side of an equilateral AB triangle taken in order. Find thei
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in rhombus ABCD, ∠AOB = 90°
Look at ΔAOB
the sum of inner angles = 180°
∠BAO + ∠AOB + ∠ABO = 180°
2x + 1 + 90 + 2x + 5 = 180°
4x + 96 = 180
4x = 84
x = 21
in rhombus ABCD, ∠AOB = 90°
Look at ΔAOB
the sum of inner angles = 180°
∠BAO + ∠AOB + ∠ABO = 180°
2x + 1 + 90 + 2x + 5 = 180°
4x + 96 = 180
4x = 84
x = 21