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3 years ago

Two parallel lines are crossed a transversal . What is the value of k

Mathematics

2 answers:

vredina [299]3 years ago

7 0

They would be alternate exterior so they would have to to be equal
2k + 11 = 131
-11 -11
2k = 120
---- -----
2k 2k
k = 60

Vitek1552 [10]3 years ago

7 0

Answer:

The value of k is 60

Option 3 is correct.

Step-by-step explanation:

Given that two parallel lines cut by transversal line

In the figure the two angles are labelled.

we have to find the value of k

Alternate Exterior Angles are those pair of angles on the outer side of each of those two lines but lie on opposite sides of the transversal line.

Here these two angles formed on the outer side and lie on opposite sides

As alternate exterior angles are equal if lines are parallel.

Therefore, the two angles labelled are equal

⇒ $2k+11=131$

Subtract 11 from both sides

$2k=131-11=120$

Divide by 2 throughout the equation

$k=\frac{120}{2}=60$

Hence, the value of k is 60

Option 3 is correct.

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Answer:

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Step-by-step explanation:

Let us consider per student charge be 'x'.

Let us consider fixed rate be 'b'

Given:

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So we can say that;

Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.

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Now we will subtract equation 1 from equation 2 we get;

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Dividing both side by 40 we get;

$\frac{40x}{40}=\frac{120}{40}\\\\x=\$3$

Now we will substitute the value of x in equation 1 we get;

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So we can say that the equation can be written as;

$y =3x+60$

Hence we can say that fixed rate is $60 and per student charge is $3.

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The answer is 120

Step-by-step explanation:

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