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Softa [21]
3 years ago
10

What is, 0.36÷0.24=?

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
1.5 will the correct answer . 
oksian1 [2.3K]3 years ago
3 0
Hey there,

Answer:

0.36 / 0.24 = 1.5

Hope this helps :D

<em>~Top♥</em>
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Finding dilations geometry​
cricket20 [7]

Answer:

3, 7

Step-by-step explanation:

6 0
3 years ago
I will give brainiest to whoever answers correctly !!
Andreyy89
Answer:
Step-by-step explanation:
We would apply the simple interest formula which is expressed as
I = PRT/100
Where
P = principal or amount borrowed
T = time in years
R = interest rate on amount borrowed.
I = interest paid.
From the given information,
Principal = $3000
T = 3 months = 3/12 = 0.25 years
R = 6 1/2 % = 6.5%
Therefore,
a) the amount that the woman pay for the use of the money is I
I = (3000 × 6.5 × 0.25)/100 = 48.75
b) The amount she repaid to the bank on the due date of the note would be
Principal + interest
= 3000 + 48.75 = $3048.75
4 0
3 years ago
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The number on two consecutively numbered gym lockers have a sum of 127. What are the locker numbers?
kaheart [24]
63 and 64 is the answer
4 0
3 years ago
Plz help loves i need
Ratling [72]

Answer:

It's the letter B :)

5 0
3 years ago
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Phyllis invested 50000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7
Elodia [21]

Answer:

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x-----> the amount invested at 5%

50,000-x -----> the amount invested at 7%

so

t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)

substitute in the formula above

2,720=x(0.05*1)+(50,000-x)(0.07*1)

solve for x

2,720=0.05x+3,500-0.07x

0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000

(50,000-x)=\$11,000

therefore

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

5 0
3 years ago
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