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mafiozo [28]
3 years ago
12

Let u=<-5,1>, v=<7,-4> find 9u-6v

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
9u -6v = 9&lt;-5, 1> -6&lt;7, -4>
.. = &lt;9*-5 -6*7, 9*1 -6*-4>
.. = &lt;-87, 33>
Fantom [35]3 years ago
5 0

Answer:

9u-6v=\langle-87, 33\rangle

Step-by-step explanation:

In order to sum the vector u and the vector v , it is convenient to define some operations.

The vector addition is given by:

u \pm v = \langle u_1 \pm v_1 , u_2\pm v_2 ,..,u_n\pm v_n\rangle

And the scalar multiplication is given by:

ku=k \langle u_1 ,u_2,..., u_n\rangle =\langle k u_1, k u_2,..., k u_n \rangle

Using the previous definitions, let's solve the problem.

First, let's find 9u :

9u=9 \langle -5,1 \rangle =\langle 9*(-5), 9*(1)\rangle=\langle-45, 9\rangle

Now, let's find 6v :

6v=6\langle 7,-4 \rangle =\langle 6*(7), 6*(-4)\rangle=\langle42, -24\rangle

Finally, let's find 9u-6v:

9u-6v=\langle-45, 9\rangle - \langle42, -24\rangle =\langle-45 -42, 9-(-24)\rangle=\langle-87, 33\rangle

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Two triangles have bases with lengths 5in and 8in.
Elis [28]

Answer:

i. The ratio of the areas of the two triangles is 5:8.

ii. The area of the larger triangle is 24 in².

Step-by-step explanation:

Let the area of the smaller triangle be represented by A_{1}, and that of the larger triangle by A_{2}.

Area of a triangle = \frac{1}{2} x b x h

Where; b is its base and h the height.

Thus,

a. The ratio of the area of the two triangles is:

\frac{area of the smaller triangle}{area of the larger triangle}

Area of smaller triangle = \frac{1}{2} x b x h

                                       = \frac{1}{2} x 5 x h

                                       = \frac{5}{2}h

Area of the lager triangle = \frac{1}{2} x b x h

                                           = \frac{1}{2} x 8 x h

                                           = 4h

So that;

Ratio = \frac{\frac{5}{2}h }{4h}

         = \frac{5}{8}

The ratio of the areas of the two triangles is 5:8.

b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;

\frac{area of the smaller triangle}{area of the larger triangle} = \frac{5}{8}

\frac{15}{A_{2} } = \frac{5}{8}

5 A_{2} = 15 x 8

       = 120

A_{2} = \frac{120}{5}

    = 24

The area of the larger triangle is 24 in².

         

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Answer:

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Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

<u>If it weights 18/5 kg on Earth then its weight  on Moon is:</u>

  • 18/5 * 1/6 = 3/5 kg
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