Solving the quadratic equation we conclude that:
- The maximum height is 45ft.
- The rocket is 18 seconds in the air.
<h3>
How to get the maximum height of the rocket?</h3>
The height of the rocket is defined by the quadratic equation:
The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:
So the maximum height is what we get when we evaluate in t = 9:
The maximum height is 45ft.
<h3>How to get the time in the air?</h3>
Now we need to solve the equation for the largest value of t:
Rewriting it, we get:
The maximum solution is what we get when:
0 = 90 - t*5
t = 90/5 = 18
The rocket is 18 seconds in the air.
If you want to learn more about quadratic equations:
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Answer:
Step-by-step explanation:
4x - 5(x + 3) Remove the brackets. Watch the - sign and -5*3
4x - 5x - 15 Combine the xs
-x - 15
Answer:
x=8
base side of isosceles triangle
y=√{8²+8²}=8√2
The measure of angle AED and angle DEB are 130 and 50degrees respectively.
The point that bisects a line divides the line into two equal parts.
If the line AB and CD intersects at E, then;
- AEC and AED supplementary
- <AEC + <AED = 180 degrees
Given that <AEC = 50 degrees
<AED = 180 - <AEC
<AED = 180 - 50
<AED = 130degrees
Similarly, <AED and <DEB are supplementary
<AED + <DEB = 180
<DEB = 180 - <AED
<DEB = 180 - 130
<DEB = 50 = <AEC (vertically opposite)
The measure of angle AED and angle DEB are 130 and 50degrees respectively.
Learn more here; brainly.com/question/14941189