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Alla [95]
3 years ago
9

if 7 is added to twice a number and this sum is multiplied by 2, the result the same as if the number is multiplied by -8 and 2

is added to product, what is the number?
Mathematics
1 answer:
Nady [450]3 years ago
7 0
X - the number

2(2x+7)=-8x+2 \\
4x+14=-8x+2 \\
4x+8x=2-14 \\
12x=-12 \\
x=\frac{-12}{12} \\
x=-1

The number is -1.
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Suppose that MNO is isosceles with base NM. Suppose also that =m∠N+4x7° and =m∠M+2x29°. Find the degree measure of each angle in
chubhunter [2.5K]

Answer:

m∠N = 51°

m∠M = 31°

m∠O = 98°

Step-by-step explanation:

It is given that ΔMNO is an isosceles triangle with base NM.

m∠N = (4x + 7)° and m∠M = (2x + 29)°

By the property of an isosceles triangle,

Two legs of an isosceles triangle are equal in measure.

ON ≅ OM

And angles opposite to these equal sides measure the same.

m∠N = m∠M

(4x + 7) = (2x + 29)

4x - 2x = 29 - 7

2x = 22

x = 11

m∠N = (4x + 7)° = 51°

m∠M = (2x + 9)° = 31°

m∠O = 180° - (m∠N + m∠M)

         = 180° - (51° + 31°)

         = 180° - 82°

         = 98°

8 0
3 years ago
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zalisa [80]
The ratio of the areas  is the ratio of the squares of the sides ( which is 10:15  or 2:3)  so the answer is
2^2 : 3^2  = 4:9.

The ratio of the perimeters = ratio of corresponding side = 2:3.

8 0
3 years ago
If all the sides of a prism are multiplied by 5, by what factor does the volume increase?
NISA [10]
I'd say increasing each side by 5 increases the volume by a factor of 125 because 5*5*5 = 125.

Example:
A 4*5*6 prism has a volume of 120

Increasing each side by a factor of five
(20*25*30) = 15,000

15,000 / 120 = 125

4 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
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Arada [10]

Answer:

I will answer the Question

Step-by-step explanation:

5 0
3 years ago
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