<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t

acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18

</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s

acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m

6 0

3 years ago

Read 2 more answers

What is the correct answer?

gavmur [86]

7x²+3y+5+9x²+11y-2

=16x²+14y+3

3 0

3 years ago

Marissa's Fashions purchases designer boots from a manufacturer for $50.88 per pair. Marissa then adds a certain amount to the p

KATRIN_1 [288]

Answer:

Markup of _66.67_ % or $ _33,92_ per pair of boots

Step-by-step explanation:

In order to find the markup per pair of boots, we need to find the sales price BEFORE tax.

That can be done simply with a cross-multiplication (106.25 represents total price with 6.25% tax, and 100 represent amount of sales before tax)

$\frac{90.10}{106.25} = \frac{x}{100}$

if we isolate x we have x = (90.10 * 100) / 106.25 = $84.80

We can then easily calculate the markup amount, since the boots were sold $84.80 and Marissa paid $50.88, that means her markup amount is $33.92.

Now, let's calculate the markup percentage by see how much $33.92 represents compared to the initial price of $50.88:

$33.92 / $50.88 = 66.67%

6 0

3 years ago