The length and width are unknown.
Let the width = w.
The length is 1 more than 3 times the width.
3 times the width is 3 * w = 3w
1 more than 3 times the width is 3w + 1
We have length = 3w + 1, and width = w
The perimeter is the sum of the lengths of the 4 sides, two lengths and two widths.
P = L + L + W + W
P = 3w + 1 + 3w + 1 + w + w
Combining like terms, we get
P = 8w + 2
We are told the perimeter is 58 in., so we set our expression for the perimeter equal to 58
8w + 2 = 58
Now we solve for w, the width.
8w = 56
w = 7
The width is 7 in.
Now we solve for the length.
L = 3w + 1
L = 3(7) + 1 = 21 + 1 = 22
The length is 22 in.
The width is 7 in.
a = 5 in
b = 12 in
c = 15 in
the lengths of the sides a, b and c
the perimeter is P = a + b + c = 5 + 12 + 15 = 32 in
let the dimensions of the new triangle be
a1 = (1/5)*5 in
b1 = (1/5)*12 in
c1 = (1/5)*15 in
the perimeter is P1 = a1 + b1 + c1 = (1/5)5 + (1/5)12 + (1/5)15 = (1/5)(5 + 12 + 15) = (1/5)P1
P1 = (1/5)P
P1/P = 1/5 = a/a1 = b/b1 = c/c1
the ratio of the perimeters is equal to the ratio of the corresponding sides.
Answer:
I think it's (3. h < 1) lmk if it's wrong
X-5y=4
+5. +5
×=9
I'm pretty sure that's how but if not I'm sorry
Answer:
89 for 4
Step-by-step explanation: