All categories

2 years ago

2x + y = −3 3x + 2y = −8

Mathematics

1 answer:

zvonat [6]2 years ago

5 0

i used elimination to solve this problem: the work is shown in the picture attached below. i got x=2 and y=-7
hoped this helped! let me know if you have any questions

You might be interested in

Find an

Mkey [24]

Counting backwards next is 1

8 0

3 years ago

Write a linear function f with the values f(0)=−3 and f(7)=11.

kotegsom [21]

Answer: f(x)= 2x -3

Step-by-step explanation:

Using the given information we can come up with two points that will be use to find the slope and y-intercept.

If you input 0 you get -3 so the point will be (0,-3)

If you input 7 you get 11 so the point will be (7,11)

Now use the points to find the difference in their y coordinates and divide it by the difference in their x coordinates to find the slope.

y coordinates: -3 - 11 = -14

x coordinates: 0 - 7 = -7

-14/-7 = 2

Since the slope is two, we will use the slope intercept formula (y = mx +b) to find the b which is the y intercept.

Use one of the points and input its x and y coordinates into the formula including the slope to solve for b.

-3= 2(0) +b

-3 = 0 + b

b = -3

f(x) is the same as y in the formula, meaning that the equation will be

f(x) = 2x -3

8 0

3 years ago

OMG PLEASE HELP IF I DONT PASS THIS I FAIL MY CLASS! HELP! 30 POINTS SHOW WORK IF U NEED TO PLEASE! thank you too anyone(PRETTY

Molodets [167]

Answer:

C seems right to me

Step-by-step explanation:

8 0

3 years ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).