All categories

3 years ago

7%of what length is 200 feet?

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Step-by-step explanation:

Let the length be x

7% of x = 200ft

7/100 × x = 200

7x/100 = 200

7x = 200 × 100

7x = 20000

x = 20000/7

x = 2,857.14

andrew11 [14]3 years ago

3 0

Step-by-step explanation:

Basically, the question is asking what number multiplied by 0.07 is equal to 200?

2857.14286 ft (round as necessary)

the way you can do this:

x(0.07)=200

isolate x by dividing 200 by 0.07 (200/0.07=2857.14286 ft)

You might be interested in

Solve the equation: 5 + 2(3 + 2x) = x + 3(x + 1)

Ann [662]

Answer:

No solutions

Step-by-step explanation:

In this question, you would be solving for x.

Solve:

5 + 2(3 + 2x) = x + 3(x + 1)

Use the distributive property.

5 + 6 + 4x = x + 3x + 3

Combine like terms.

11 + 4x = 4x + 3

Subtract 4x from both sides.

11 = 3

Since we don't have an "x value", there are no solutions.

"No solutions" would be your answer.

5 0

3 years ago

Julie spent 1/6 of her money on books , 1/3 of the remainder on a dress and saved the rest.

Lana71 [14]

The answers are 5/9 and $234.

6 0

3 years ago

Read 2 more answers

Nora makes $3,000 a month. The key chart below shows how much she spends her money. How much money does Nora spend on each categ

Eduardwww [97]

Rent: $ 780
Food:$ 900
Medical:$ 450
Clothes:$ 300
Miscellaneous:$ 570

8 0

3 years ago

Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

7 0

3 years ago

2 boxes has 50 pieces of candy and the other 2 boxes have 20 pieces of candy. how could ivanna solve for,c, the total number of

Norma-Jean [14]

C= 50y+20x
Where y is the number of boxes holding 50 pieces each and x is the number of boxes holding 20 pieces each.

7 0

3 years ago