Add the five to each side.
then square it to get rid of the square root
2x+13=(5+x)^2
2x+13=x^2+10x+25
2x=x^2+10x+12
x^2+8x+12=0
(x+6)(x+2)
x+6=0
x+2=0
answers are -2 and -6, however, when pluging -6 in it doesnt work, so it is only -2.
Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Answer:
The variable Y represents the number of meters of string in the third yoyo
Step-by-step explanation:
In this equation y stands for the unknown variable. The equation tell you that hope made 3 different yo-yos so the number of yo-yos hope made isn't unknown, meaning, it cant be the first answer. The problem also tells you that hope used a total of 4 meters of string which means that the total number of string used isn't the unknown variable. The number of meters of string in the third yo-yo is the only number that isn't. This makes the number of sting used in the third yo-yo the unknown variable, making it y.
Answer:

Step-by-step explanation:
To find the inverse of a function f (x) follow the steps below:
1) Make y = f (x)

2) Solve for the variable x



3) Exchange the variable x with the variable y

4) Make 

Finally, the inverse of the function f (x) is: 
Answer:
The maximum number of packages that can be made with each package have same number of each item is = 6
Step-by-step explanation:
Given:
Mr. Harris has 48 pencils and 30 notebooks.
To find the number of packages he can make with each package have same number of each item.
Solution:
Number of pencils = 48
Number of notebooks = 30
In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.
<em>To find the G.C.F., we will list down the prime factors of each.</em>


We find that the G.C.F. =
= 6
Thus, the maximum number of packages that can be made with each package have same number of each item is = 6