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2 years ago

Please help I’ll give you brainiest !

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

Answer:

{290,315,340, 365, 390, 415, 440, 465} That's the answer. Its hard for me to explain how i got it.

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Find the opposite integer of 6

Morgarella [4.7K]

The opposite integer is -6 because if it's positive then the opposite is negative

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3 years ago

What is the equation of this line?

elena-14-01-66 [18.8K]

Answer:

A) y = 4/3 x - 1/3

Step-by-step explanation:

(4,5) and (-2,-3)

Slope = (5 + 3)/(4 + 2)

= 8/6

= 4/3

Equation

y + 3 = 4/3(x + 2)

y + 3 = 4/3 x + 8/3

y = 4/3 x + 8/3 - 9/3

y = 4/3 x - 1/3

Answer:

y = 4/3 x - 1/3

8 0

3 years ago

Solve the equation for the value of x; 8x + 12 = 52.

777dan777 [17]

The answer is c: x=5

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2 years ago

Read 2 more answers

What is the length of the hypotenuse of the triangle? triangle A B C. Side A C is 7 centimeters and side B C is 3 centimeters. H

Maksim231197 [3]

Answer: √58 cm or 7.62 cm

Step-by-step explanation:

The Pythagorean Theorem is a²+b²=c². Since we are given the lengths of a and b, we can plug them into this formula to find the length of the hypotenuse.

7²+3²=c²

49+9=c²

58=c²

c=√58 or 7.62 cm

6 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago