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Mekhanik [1.2K]
4 years ago
7

Using eq. 7: calculate the buffer capacity (BC) of your buffer solution before and after dilution with water, and enter the valu

es obtained below. Remember that before dilution the water volume in the flask was 25 mL. After dilution, the volume was 35 mL. The number of moles of weak acid and conjugate base will depend on the amounts added to the flask. You're weak acids molar mass is 234 and that of the conjugate base is 256.

Chemistry
1 answer:
alexdok [17]4 years ago
4 0

Answer:

0.1256 - before dilution

0.0897 - after dilution

Check attachment for calculation

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It is because water is a liquid form.
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4 years ago
Write a balanced equation for the dissolution of sodium carbonate (Na2CO3) in water. Find the number of moles of Na+ produced wh
DochEvi [55]

Answer:

in the presence of water H2O

Na2CO3 (S) --> 2Na+ (aq)+ (CO3)2-(aq)

One mole of sodium carbonate produces two moles of Na+ ions

Therefore 0.207 moles produces 0.414 moles of Na+ ions

= 0.414 moles of Na+ ions

Explanation:

In water

Na2CO3 --> 2Na+ (aq)+ (CO3)2-(aq)

In a limited reaction, the carbonate ion reacts with the water molecules as follows

(CO3)2-(aq) + H2O←→HCO3-(aq) + OH-(aq)

sodium carbonate or soda ash dissolves in water to give 2 sodium cations and one carbonate anion

4 0
3 years ago
Which member of each pair is the stronger base? part a ethylamine or aniline ethylamine or aniline ethylamine aniline request an
Vladimir79 [104]
Lowery-Bronsted theory is applied here. Acc. to this theory Base accepts protons and Acids donate proton.

Part 1: 
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Part 2:
In this case the alkyl groups attached to -NH₂ (in ethylamine) and -O⁻ (in ethoxide are same (i.e. CH₃-CH₂-). Ethoxide is more basic than ethylamine because ethoxide is a conjugate base of ethanol (pKa value of ethanol = 15.9 very weak acid) and the conjugate base of weak acid is always a strong base. Secondly, the oxygen atom more Electronegative than Nitrogen atom can attract more electron cloud from alkyl group as compared to Nitrogen in ethylamine. Hence, oxygen in ethoxide attains greater electron cloud than the nitrogen in ethylamine. Therefore, it is more basic than ethylamine.

5 0
4 years ago
How many liters of water do we need to add to 5.00 moles to get a 0.648 M solution?
Tanya [424]

Answer: This is a typical acid/base equilibrium problem, that involves the use of logarithms.

Explanation:We assume that both nitric acid and hydrochloric acid dissociate to give stoichiometric

H

3

O

+

.

Moles of nitric acid:

26.0

×

10

−

3

⋅

L

×

8.00

⋅

m

o

l

⋅

L

−

1

=

0.208

⋅

m

o

l

H

N

O

3

(

a

q

)

.

And, moles of hydrochloric acid:

88.0

×

10

−

3

⋅

L

×

5.00

⋅

m

o

l

⋅

L

−

1

=

0.440

⋅

m

o

l

H

C

l

(

a

q

)

.

This molar quantity is diluted to

1.00

L

. Concentration in moles/Litre =

(

0.208

+

0.440

)

⋅

m

o

l

1

L

=

0.648

⋅

m

o

l

⋅

L

−

1

.

Now we know that water undergoes autoprotolysis:

H

2

O

(

l

)

⇌

H

+

+

O

H

−

. This is another equilibrium reaction, and the ion product

[

H

+

]

[

O

H

−

]

=

K

w

. This constant,

K

w

=

10

−

14

at

298

K

.

So

[

H

+

]

=

0.648

⋅

m

o

l

⋅

L

−

1

;

[

O

H

−

]

=

K

w

[

H

+

]

=

10

−

14

0.648

=

?

?

p

H

=

−

log

10

[

H

+

]

=

−

log

10

(

0.648

)

=

?

?

Alternatively, we know further that

p

H

+

p

O

H

=

14

. Once you have

p

H

,

p

O

H

is easy to find. Take the antilogarithm of this to get

[

O

H

−

]

.

Answer link  

4 0
3 years ago
I NEED HELP PLEASE, THANKS!! :)
In-s [12.5K]

Answer:

B) microscopic

Explanation:

A scanning tunneling microscope allows imaging of microscopic particles.

5 0
4 years ago
Read 2 more answers
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