Answer:
C) 0.800 mol
Explanation:
In order to <u>convert from moles of Al₂O₃ into moles of Al</u>, we'll need to use<em> the stoichiometric coefficients</em>, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:
- 0.400 mol Al₂O₃ *
= 0.800 mol Al
So the correct answer is option C).
<u>Out of all given option, the following statements are true about a system:</u>
- A system is a group of objects analyzed as one unit.
- Energy that moves across system boundaries is conserved
Answer: Option A and B
<u>Explanation:</u>
A system is "a complicated item whose parts or segments are identified with probably a portion of different segments", it very well may be material or calculated. All systems have piece, structure, and condition, yet just material systems have instruments (or forms), and just some material systems have shape.
As per systems, all articles are systems or segments of another system. For instance, a nuclear core is a physical material system made out of protons and neutrons related by solid atomic association; a cell is a natural material system made out of related organelles by non-covalent synthetic securities and metabolic pathways; and a logical hypothesis is a consistent reasonable system made out of theories, definitions, and hypotheses related by relationship and conclusion.
Water molecules are highly packed and are always near each other.
D.
Misinterpretation of scientific knowledge for the influence of public opinion has been a repeating problem over the past, and usually creates a rift between the scientific community and the general public.
Answer:1.
1.Balanced equation
C4H10 + 9 02 ==> 5H20 +4CO2
2. Volume of CO2 =596L
Explanation:
1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;
CxHy +( x+y/4) O2 ==> y/2 02 + xCO2
Where x and y are number of carbon and hydrogen atoms respectively.
For butane (C4H10)
x=4 and y=10
Therefore
C4H10 + 9 02 ==> 5H20 +4CO2
2. Mass of butane = 0.360kg
Molar mass of C4H10 = ( 12×4 + 1×10)
= 48 +10=58g/mol= 0.058kg/mol
Mole = mass/molar mass
Mole = 0.360/0.058= 6.2moles
From the stoichiometric equation
1mole of C4H10 will gives 4moles of CO2
Therefore
6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2
Using the ideal gas equation
PV=nRT
P= 1.0atm
V=?
n= 24.8mol.
R=0.08206atmL/molK
T=20+273=293
V= 24.8 × 0.08206 × 293
V= 596L
Therefore the volume of CO2 produced is 596L
