Answer:
option 2 is correct answer. its nitrogen.
In response of what like what’s the full clear question
Moles of Hydrogen present: 100 / 2 = 50 moles
Moles of Nitrogen present: 200 / 28 = 7.14 moles
Hydrogen required by given amount of nitrogen = 7.14 x 3 = 21.42 moles
Hydrogen is excess so we will calculate the Ammonia produced using Nitrogen.
Molar ratio of Nitrogen : Ammonia = 1 : 2
Moles of ammonia = 7.14 x 2 = 14.28 moles
Answer:
N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e
Explanation:
Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.
The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.
Answer:
Explanation:
Given that
d= 35 μm ,yield strength = 163 MPa
d= 17 μm ,yield strength = 192 MPa
As we know that relationship between diameter and yield strength
d = diameter
K =Constant
So now by putting the values
d= 35 μm ,yield strength = 163 MPa
------------1
d= 17 μm ,yield strength = 192 MPa
------------2
From equation 1 and 2
K=394.53
By putting the values of K in equation 1
Now when d= 12 μm
