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3 years ago

What is the answer of (X^2+x-10)-(3x^2-4x-2)=

Mathematics

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

-2x^2 + 5x - 8

Step-by-step explanation:

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Select the correct answer.

Hitman42 [59]

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the function is not given. So, I will make an assumption.

A quadratic function is represented as:

$f(x) = ax^2 + bx + c$

If $a > 0$ , then the function has a minimum x value

E.g. $f(x) = 4x^2 - 5x + 8$ ------ $4 > 0$

Else, then the function has a maximum x value

E.g. $f(x)= -4x^2 -5x + 8$ ---- $-4 < 0$

The maximum or minimum x value is calculated using:

$x = -\frac{b}{2a}$

For instance, the maximum of $f(x)= -4x^2 -5x + 8$ is:

$x = -\frac{-5}{2*-4}$

$x = -\frac{5}{8}$

So, the maximum of the function is:

$f(x)= -4x^2 -5x + 8$

$f(-\frac{5}{8}) = -4 * (-\frac{5}{8})^2 - 5 *(-\frac{5}{8}) +8$

$f(-\frac{5}{8}) = 9.5625$

8 0

3 years ago

A circle has the radius of 5 feet.what is the circumference of a bigger

DerKrebs [107]

Answer:

12.5 feet

Step-by-step explanation:

3 0

4 years ago

The coordinates of the vertices of △GHI are G(−7,2), H(−2,2), and I(−2,8). Find the side lengths to the nearest hundredth and th

adelina 88 [10]

Answer:

GH = 5, HI = 6, GI ≈ 7.81

m∠H = 90°, m∠G ≈ 50°, m∠I ≈ 40°

Step-by-step explanation:

4 0

3 years ago

The highest temperature ever recorded in Death Valley, California, was 121°, while the lowest ever recorded there was 13° below

s344n2d4d5 [400]

Answer:

The answer is C

Step-by-step explanation:

Remember it says 13' below zero, and 121' is the highest temperature.

7 0

3 years ago

Read 2 more answers

Prove that csc x - cot x is the same as (sin x)/(1 + cos x)

Lera25 [3.4K]

$\csc x-\cot x=\dfrac{\sin x}{1+\cos x}\\\\L_s=\dfrac{1}{\sin x}-\dfrac{\cos x}{\sin x}=\dfrac{1-\cos x}{\sin x}\\\\R_s=\dfrac{\sin x}{1+\cos x}\cdot\dfrac{1-\cos x}{1-\cos x}=\dfrac{\sin x(1-\cos x)}{1^2-\cos^2x} =\dfrac{\sin x(1-\cos x)}{1-\cos^2x}\\\\=\dfrac{\sin x(1-\cos x)}{\sin^2x}=\dfrac{1-\cos x}{\sin x}\\\\L_s=R_s$

$\text{Used:}\\\\\csc x=\dfrac{1}{\sin x}\\\\\cot x=\dfrac{\cos x}{\sin x}\\\\a^2-b^2=(a-b)(a+b)\\\\\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

8 0

3 years ago