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mina [271]
3 years ago
12

How do you find the theoretical probability​

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0
Where is the question? Experimental probability means by legit doing an experiment, while theoretical is just predicting your results.
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in a major study by the statistics classes at Washington High School, city parking spaces were examined for compliance with the
aev [14]

Answer:

0.4224 = 42.24% probability he will find an expired meter BEFORE the 3rd one

Step-by-step explanation:

For each car, there is a 24% probability that it had expired parking meters.

What is the probability he will find an expired meter BEFORE the 3rd one?

Three possible outcomes:

Two expired(each with 24% probability)

First expired(24% probability) and second not(76% probability)

First not(76% probability) and second expired(24% probability). So

p = 0.24^2 + 2*0.24*0.76 = 0.4224

0.4224 = 42.24% probability he will find an expired meter BEFORE the 3rd one

5 0
3 years ago
What is the slope intercept form of through: (-4,-5) slope: 5/4
Marianna [84]

Answer:

y = 5/4 x

Step-by-step explanation:

We already know the slope, so now we need to find the y-intercept. To do that, you need to simply plug the coordinates into the equation which is

y = 5/4 x + b

-5 = 5/4 (-4) + b

-5 = -5 + b

0 = b

y = 5/4 x + 0 or simply just y = 5/4 x.

8 0
3 years ago
What is 8x+2y=-10 in slope intercept form??
Mandarinka [93]

Answer:

y=-4x-5

Step-by-step explanation:

thats how you write it in y=mx+b form

h ope this helps.       :)

4 0
3 years ago
Help me out :)) 2(5x-1)+3x !! simplify !!
djyliett [7]
13x-2. 2•5x=10x 2•-1=-2. 10x-2+3x=13x-2
6 0
3 years ago
Read 2 more answers
A 20 kg sphere is at the origin and a 10 kg sphere is at x = 20 cm. At what position on the x-axis could you place a small mass
Yuri [45]
<h2>The small mass should be placed at x = 11.72 cm or x = 68.28 cm </h2>

Step-by-step explanation:

Let the small mass be m and position on x axis be y.

A 20 kg sphere is at the origin.

Distance to 20 kg mass = y

A 10 kg sphere is at x = 20 cm

Distance to 10 kg sphere = 20 - y

We have forces between them are equal

We have gravitational force   

                    F=\frac{GMm}{r^2}              

          Where G =  6.67 x 10⁻¹¹ N m²/kg²

                      M = Mass of body 1

                      M = Mass of body 2

                      r = Distance between them

Here we have

            \frac{G\times 20\times m}{y^2}=\frac{G\times 10\times m}{(20-y)^2}\\\\800-80y+2y^2=y^2\\\\y^2-80y+800=0\\\\y=68.28cm\texttt{ or }y=11.72cm

So the small mass should be placed at x = 11.72 cm or x = 68.28 cm

5 0
3 years ago
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