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UkoKoshka [18]
3 years ago
7

Can someone break this down for me?!

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

The answers are in the question.

Step-by-step explanation:

The wording can be off-putting but the answers are mostly there for you. It says that when the wind was at the tail of the plane, the travel was hastened to 5 hours instead of six. Is the rate of speed with the wind in favor of the plane is r+21, then it stands to reason that traveling AGAINST the wind will cause the rate to drop to r-21. Taking the average of the two travel times (5 and 6 hours each), we get 5.5 hours. Since speed is distance divided by time, the speed of the plane in still air will be <em>d</em> / 5.5

Be sure to label the speed as mph.

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How many real solutions are there for the function graphed below?
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1.
A graph is formed by plotting all pairs (x,y), such that y is f(x), for a certain function f.

for example:

Take a look at the graph. (x, y)=(3, 5) is on the graph. This means that f(3)=5      (because f(x)=y)

2.
The real solutions of a function f, are those points x, such that f(x)=0.

in the graph we see no point (x, 0), so there are no real solutions.


Answer: <span>No Real Solution</span>
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3 years ago
Solve this equation<br> y= 2x<br> x= -y + 6
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Answer:

y=x+6

Step-by-step explanation:

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What are you gonna do is across the x

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A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
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Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
3 years ago
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