Name two streets that intersect but do not appear to be perpendicular.
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If two lines are perpendicular, then their slopes have a product of -1 or you could say they are opposite signed reciprocals of each other.
The given equation has a slope of -3. We know this because it is in slope-intercept form y = mx + b ...y = (slope)x + (y-intercept).
so taking the slope -3...the opposite signed reciprocal would be +
Now we have a slope and a point... we can use them to find the b (y-intercept)
x = 4, y = 3, and m =
Using the common denominator fraction for 3, we subtract 4/3 from both sides
plug the values for m and b into the slope intercept form
The given equation has a slope of -3. We know this because it is in slope-intercept form y = mx + b ...y = (slope)x + (y-intercept).
so taking the slope -3...the opposite signed reciprocal would be +
Now we have a slope and a point... we can use them to find the b (y-intercept)
x = 4, y = 3, and m =
Using the common denominator fraction for 3, we subtract 4/3 from both sides
plug the values for m and b into the slope intercept form