if a triangle has sides measuring 8 inches and 15 in and has a hypotenuse measuring 17 in what is the ratio in simplest form of
1 answer:
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X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6