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3 years ago

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the

Mathematics

2 answers:

Roman55 [17]3 years ago

8 0

it can also be explained as D on edg if you still needed the answer :)

liubo4ka [24]3 years ago

7 0

Answer:

The element you add is $b^2 / 4a$

Step-by-step explanation:

The element you add is $b^2 / 4a$

Remember that

$a x^2 + bx +c \\= a ( x^2 +(b/a)x ) + c$

So, in order to complete the square you add $(b/2a)^2$

But when you multiply times $a$ you get

$b^2 / 4a$

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In 2001 , chipper had 102 runs batted in. In 2008, Chipper had only 75 runs batted in. Calculate the percent change in runs batt

DerKrebs [107]

Answer:

The percent change in runs batted in from 2001 to 2008 is 26.47%

Step-by-step explanation:

The number of runs chipper batted in the year 2001 = 102 runs

The number of runs chipper batted in the year 2008 = 75 runs

Here, so the Change in the runs batted

= Runs Batted in year 2001 - Runs batted in the year 2008

= 102 runs - 75 runs = 27 runs

Now, The percentage change in the run = $= \frac{\textrm{Change in the batted run from 2001 to 2008}}{\textrm{Total number of batted runs in 2001}} \times 100$

= $\frac{27}{102} \times 100 = 26.47$

or, The percentage change = 26.47%

Hence, the percent change in runs batted in from 2001 to 2008 is 26.47%

5 0

3 years ago

solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$

Thus, the system of three equations is

$\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.$

From the last equation:

$y=-6$

Substitute it into the second equation:

$16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3$

Substitute y = -6 and z = -3 into the first equation:

$x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5$

7 0

3 years ago

9. You have a globe that has a diameter of 22 inches. Find the volume of

Savatey [412]

I think the answer is that what i think

3 0

3 years ago

Geometry. Please help ASAP.

neonofarm [45]

Please see the pic, I'd solved your question in it.

6 0

3 years ago

Exploring the graph of y equals cosine Theta

irga5000 [103]

Answer: see below

<u>Step-by-step explanation:</u>

The coordinates on the Unit Circle are (cos, sin). Since we are focused on cosine, we only need to focus on the left side of the coordinate. The cosine value (left side) will be the y-value of the function y = cos x

Use the quadrangles (angles on the axes) to represent the x-values of the function y = cos x.

Quadrangles are: 0°, 90°, 180°, 270°, 360° <em>(360° = 0°)</em>

Together, the coordinates will be as follow:

$\boxed{\begin{array}{c||c|c||c}\underline{(cos,sin)}&\underline{x=angle}&\underline{y=cosx}&\underline{\quad (x,y)\quad}\\(1,0)&0^o&1&(0^o,1)\\(0,1)&90^o&0&(90^o,0)\\(-1,0)&180^o&-1&(180^o,-1)\\(0,-1)&270^o&0&(270^o,0)\\(1,0)&360^o&1&(360^o,1)\end{array}}$

8 0

3 years ago