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3 years ago

0.5(x^4-7)+16 what is the answer your answer should contain decimals.

Mathematics

1 answer:

svlad2 [7]3 years ago

5 0

The answer should be 0.5x^4+12.5

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For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp

Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

$\frac{1}{365}$

a) Probability that exactly 3 people have same birthday = $\frac{1}{365^3}$

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = $\frac{1}{365^3}$

Expected value of days = np = $\frac{1}{365^2}$

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0

4 years ago

Write an equation of the line with the given y-intercept and the slope in slope-intercept form m=1/3; b=-1

Over [174]

Answer:

y= 1/3x - 1

Step-by-step explanation:

1/3 is slope so m and -1 is the y-intercept

8 0

3 years ago

The class of 2004 holds a reunion each year. In 2005, 87.5% of the 120 graduates attended. In 2006, 90 students went, and in 200

vampirchik [111]

Answer:

15 students

Step-by-step explanation:

% of students attended reunion in 2005 = 87.5% of 120

no of students attended reunion in 2005 = 87.5/100 * 120 = 105.

no of students attended reunion in 2006 = 90

no of students attended reunion in 2007 = 75

So , the series for the given year is

105, 90, 75

we can see that this arithmetical progression series

in arithmetical progression series

common difference is = nth term - (n-1)th term

lets takes 3rd and second term as nth term and (n-1)th term

common difference(d) is =75 - 90 = -15

n th term for any arithmetical progression series is given by

nth term = a + (n-1) d

where a is the first term

n is the nth term

d is the common difference

we have to calculate number of students in reunion of of 2010

as reunion began from 2005

2005,2006,2007,2008,2009,2010

so, 2010 is 6th term in series of 105, 90, 75....

6th term = a + (n-1) d

a is 90

6th term = 90+ (6-1)* -15

6th term = 90+ (5)* -15 = 90 - 75 = 15.

Thus, 15 students will attend reunion of 2010

5 0

3 years ago

Help!!! Cubes! Hurry ima fail

aksik [14]

Answer:

your answer is 9

Step-by-step explanation:

Just trust me!

4 0

3 years ago

Read 2 more answers

Addition ar<br> ASSIGNMENT<br> f(x) = x² + 1<br> g(x)= 5-2<br> (f+g)(x) =

ycow [4]

If that is an “f of g of x” it should be 10

6 0

4 years ago