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3 years ago

Solve for x in the diagram below. 3x 75° T =

Mathematics

2 answers:

leva [86]3 years ago

7 0

Answer:
3x+75=180
3x=180-75
3x=105
x=105/3
x=35

LiRa [457]3 years ago

3 0

Answer:

x=35

Step-by-step explanation:

The 2 angles are on a straight line together. This means they are supplementary. When they are added together, they must equal 180 degrees.

3x+75=180

We want to find out what n is. In order to do this, we have to get n by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.

75 is being added to 3x. The opposite of addition is subtraction. Subtract 75 from both sides.

3x+75-75=180-75

3x=180-75

3x=105

x is being multiplied by 3. The opposite of multiplication is division. Divide both sides by 3.

3x/3=105/3

x=105/3

x=35

x is equal to 35.

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3 years ago

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katrin [286]

Answer:

3. Speed is based on a specific direction

Step-by-step explanation:

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3. Speed is based on a specific direction

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3 years ago

Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used

ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes head start

Senn needs to give Ms. Beetle 18.4 minutes head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0

3 years ago